Was I correct?- please help, thanks

Evaluate. (-2 1/4)^2

balandron [24]

Answer:

$5 \frac{1}{16}$

Step-by-step explanation:

I did this before. Also sometimes once I look at the question I just find out the answer without steps.

6 0

3 years ago

Write each equation in standard form y-2=3(x-1)

Free_Kalibri [48]

Standard formula: Ax + By = C
y = 3x -3 + 2
y - 3x = -1 is the answer

hope this helps

8 0

4 years ago

You deposited 8500 dollars in a saving account that earns a simple interest rate. what interest rate do you need to be paid if y

V125BC [204]

Answer:

23.75%

Step-by-step explanation:

Use formula

$I=P\cdot r\cdot t,$

where

I = interest,

P = principal,

r = rate (as decimal),

t = time (in years).

In your case,

$I=\$8,500\\ \\P=\$10,093.75\\ \\t=60\text{ months}=5 \text{ years}$

Substitute:

$10,093.75=8,500\cdot r\cdot 5\\ \\r=\dfrac{10,093.75}{8,500\cdot 5}=0.2375=23.75\%$

6 0

4 years ago

At a unit price of $900, the quantity demanded of a certain commodity is 75 pounds. If the unit price increases to $956, the qua

Nady [450]

Answer:

1) The demand equation is $x=-0.25p+300$

2) The price when no consumers willing to buy this commodity is $1200.

3) The quantity of the commodity would consumers take if it was free is 300 pounds.

Step-by-step explanation:

Given : At a unit price of $900, the quantity demanded of a certain commodity is 75 pounds. If the unit price increases to $956, the quantity demanded decreases by 14 pounds.

To find :

1) The demand equation ?

2) At what price are no consumers willing to buy this commodity?

3) According to the above model, how many pounds of this commodity would consumers take if it was free?

Solution :

1) According to question,

p is the unit price and x is the quantity demanded for this commodity in pounds.

Let, $p_1=\$900$ and $x_1=75\text{ pounds}$

and $p_2=\$956$ and $x_2=75-14=61\text{ pounds}$

To find the demand equation we apply two point slope form,

$(x - x_1)=\frac{(x_2-x_1)}{(p_2-p_1)}\times(p-p_1)$

Substitute the values,

$(x - 75)=\frac{61-75}{956-900}\times(p-900)$

$(x - 75)=\frac{-14}{56}\times(p-900)$

$(x - 75)=\frac{-1}{4}\times(p-900)$

$x-75=-\frac{1}{4}p+225$

$x=-\frac{1}{4}p+300$

$x=-0.25p+300$

The demand equation is $x=-0.25p+300$

2) For no consumers,

Substitute x=0 in demand equation,

$0=-0.25p+300$

$0.25p=300$

$p=\frac{300}{0.25}$

$p=1200$

The price when no consumers willing to buy this commodity is $1200.

3) For free,

Substitute p=0 in demand equation,

$x=-0.25(0)+300$

$x=300$

The quantity of the commodity would consumers take if it was free is 300 pounds.

3 0

3 years ago

jeromes rain gauge showed 13 9/10 centimeters at the end of last month. at the end of this month, the rain gauge showed 15 3/10

Ne4ueva [31]

It rained 1 and 4/10 centimeters. You have to first figure out what adds up to 14, which is 1/10. Then you add 1 to get 15 and 3/10 to get 15 3/10.

3 0

3 years ago