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arlik [135]
3 years ago
8

The sides of △FGH are FG = 6 x+ 7, GH = 8x - 5, and FH = 10x - 11. If the perimeter of △FGH is 87, list the angles in order from

largest to smallest.
Mathematics
1 answer:
irga5000 [103]3 years ago
4 0

Answer:

From largest to smallest: FG, FH, GH

Step-by-step explanation:

Given

FG = 6x + 7

GH = 8x - 5

FH = 10x - 11

Perimeter = 87

Required

Order the sides in descending order

First, we need to solve for x.

Perimeter of FGH is calculated as thus:

Perimeter = FG + GH + FH

Substitute values for FG, GH, FH and Perimeter

87 = 6x + 7 + 8x - 5 + 10x - 11

Collect Like Terms

87 - 7 + 5 + 11= 6x + 8x + 10x

96= 24x

Reorder

24x = 96

Divide through by 24

x = 96/24

x = 4

Substitute 4 for x in FG, GH and FH

FG = 6x + 7

FG = 6 * 4 + 7

FG = 24 + 7

FG =31

GH = 8x - 5

GH = 8 * 4 - 5

GH = 32 - 5

GH = 27

FH = 10x - 11

FH = 10*4 - 11

FH = 40 - 11

FH = 29

In order of arrangement in descending order, we have:

FG =31    FH = 29     GH = 27

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Answer:

Step-by-step explanation:

Equal

4 0
3 years ago
I have no clue how to do this please help
mel-nik [20]

Answer:

Max = (6,0); min = (-2, 4)  

Step-by-step explanation:

1. Summarize the constraints

\text{Constraints} = \begin{cases}(a)\qquad 2x - y  & \leq 12\\(b)\qquad 4x+ 2y & \geq 0\\(c) \qquad x + 2y  & \leq 6\\ \end{cases}

2. Optimization equation

z = 5x + 2y

3. Graph the constraints to identify the feasible region

See the figure below.

The "TRUE" regions for each graph are the shaded areas to the side of the line indicated by the arrows.

The "feasibility region" is the dark green area where all three areas overlap and all three conditions are satisfied.

5. Determine the points of intersection among the constraints  

(i) Constraints (a) and (b)

\begin{array}{rcr}2x - y  & = & 12\\4x + 2y & = & 0\\4x - 2y & = & 24\\8x&=&24\\x & = & \mathbf{3}\\6 - y & = & 12\\-y & = &6\\y & = & \mathbf{-6}\\\end{array}\\

The lines intersect at (3,-6).

(ii) Constraints (a) and (c)

\begin{array}{rcr}2x - y  & = & 12\\x + 2y & = & 6\\4x - 2y & = &24\\5x & = & 30\\x & = & \mathbf{6}\\6 + 2y & = & 6\\2y & = &0\\y & = & \mathbf{0}\\\end{array}

The lines intersect at (6,0).

(iii) Constraints (b) and (c)

\begin{array}{rcr}4x+ 2y &= & 0\\x + 2y  &=& 6\\3x & = &  -6\\x & = & \mathbf{-2}\\-2 +2y & = & 6\\2y & = &8\\y & = & \mathbf{4}\\\end{array}

The lines intersect at (-2,4).

6. Determine the x- and y-intercepts of the feasible region

The five black dots at (3,-6), (6,0), and (-2,4) are the vertices of the polygon that represents the feasible region.

Each vertex is a possible maximum or minimum of z.  

7. Calculate the maxima and minima

Calculate z at each of the vertices.

(i) At (-2,4)

z = 5x + 2y = 5(-2) + 2(4) = -10 + 8 = 2

(ii) At (3,-6)

z =  5(3) + 2(-6) = 15 - 12 = 3

(iii) At (6,0)

z = 5(6)+ 2(0) = 30 + 0 = 30

The maximum of z occurs at (6,0).

The minimum of z occurs at (-2, 4).

 

7 0
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