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3 years ago

HELP ME ASAP.. MY TEACHER IS ASKING FOR THE ANSWER

Mathematics

1 answer:

Solnce55 [7]3 years ago

5 0

Answer:

a) 10.7 cm

b) 11.6 cm

c) 29.9 cm²

Step-by-step explanation:

a) sin(α)/a = sin(β)/b

sin(∠BCD)/BD = sin(DBC)/DC

sin(41°)/BD = sin(55°)/13.4

BD = 13.4*sin(41°)/sin(55°) = 10.73 cm ≈ 10.7 cm

b) From ΔBCD , ∠BDC = 180-(41+55) = 84°

∠ABD and ∠BDC are alternate interior angles, so they are congruent, and

∠ABD = ∠BDC = 84°

AD²= AB² + BD² - 2*AB*BD*cos (∠ABD) =

= 5.6² + 10.73² - 2*5.6*10.73*cos(84°) = 133.93 cm²

AD =√(133.93) ≈11.6 cm

c) Area(ADB) = (1/2)*AB*BD*sin(∠ABD)=(1/2)*5.6*10.73*sin(84°) ≈ 29.9 cm²

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3 years ago

Read 2 more answers

Ty has 5 goats and 19 carrots. He gives each goat the same number of carrots, and he uses as many carrots as he can. How many ca

velikii [3]

Each goat gets 3 carrots.

After giving 3 carrots to each of the goat, 4 carrots are left with Ty in total.

Step-by-step explanation:

Here, the total number of carrots = 19

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So, in the given condition:

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5 is the DIVISOR

Now, dividing 19 by 5, we get:

19 = 5 x 3 + 4

Here, 3 = Quotient

4 = Remainder

So, by the given equation. we can say that:

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3 years ago

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3 years ago

What is a equivalent fraction for 3/9?

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1/3 = 2/6 = 3/9 = 4/12 = 5/15 = 6/18 = 7/21 = 8/24 = 9/27 = 10/30 = 11/33 = 12/36 = 13/39 = 14/42 = 15/45 = 16/48 = 17/51 = 18/54 = 19/57 = 20/60
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3 years ago

There are 2,000 eligible voters in a precinct. A total of 500 voters are randomly selected and asked whether they plan to vote f

Ann [662]

Answer:

$0.7 - 2.58 \sqrt{\frac{0.7(1-0.7)}{500}}=0.647$

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And the 99% confidence interval would be given (0.647;0.753).

So the correct answer would be:

a. 0.647 and 0.753

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

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The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Solution to the problem

The estimated population proportion for this case is:

$\hat p = \frac{350}{500}=0.7$

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 99% confidence interval the value of $\alpha=1-0.99=0.01$ and $\alpha/2=0.005$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=2.58$

And replacing into the confidence interval formula we got:

$0.7 - 2.58 \sqrt{\frac{0.7(1-0.7)}{500}}=0.647$

$0.7 + 2.58 \sqrt{\frac{0.7(1-0.7)}{500}}=0.753$

And the 99% confidence interval would be given (0.647;0.753).

So the correct answer would be:

a. 0.647 and 0.753

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2 years ago

HELP ME ASAP.. MY TEACHER IS ASKING FOR THE ANSWER ​

HELP ME ASAP.. MY TEACHER IS ASKING FOR THE ANSWER