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frutty [35]
3 years ago
12

Ccacacvssvvssjdsvshxb de s zzz dat herh

Mathematics
1 answer:
KATRIN_1 [288]3 years ago
6 0

Answer: gjnyujhgfdrjhg;flhigobkhyjnhkmk,

Step-by-step explanation:

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Thanks for the help! Been stuck on this one for a little while.
igor_vitrenko [27]

Answer:

B. \sqrt{14}

Step-by-step explanation:

Since 3.74 is rounded to the hundredths place, it is not the ideal exact solution for m^2 = 14.

To solve for m you would have to square root m and 14, which gives you \sqrt{14}. This is the best answer for the problem.

8 0
3 years ago
A random sample of 850 births included 434 boys. Use a 0.10 significance level to test the claim that 51.5​% of newborn babies a
Molodets [167]

Answer:

A

Null hypothesis: H0: p = 0.515

Alternative hypothesis: Ha ≠ 0.515

z = -0.257

P value = P(Z<-0.257) = 0.797

Decision; we fail to reject the null hypothesis. That is, the results support the belief that 51.5​% of newborn babies are​ boys

Rule

If;

P-value > significance level --- accept Null hypothesis

P-value < significance level --- reject Null hypothesis

Z score > Z(at 90% confidence interval) ---- reject Null hypothesis

Z score < Z(at 90% confidence interval) ------ accept Null hypothesis

Step-by-step explanation:

The null hypothesis (H0) tries to show that no significant variation exists between variables or that a single variable is no different than its mean. While an alternative Hypothesis (Ha) attempt to prove that a new theory is true rather than the old one. That a variable is significantly different from the mean.

For the case above;

Null hypothesis: H0: p = 0.515

Alternative hypothesis: Ha ≠ 0.515

Given;

n=850 represent the random sample taken

Test statistic z score can be calculated with the formula below;

z = (p^−po)/√{po(1−po)/n}

Where,

z= Test statistics

n = Sample size = 850

po = Null hypothesized value = 0.515

p^ = Observed proportion = 434/850 = 0.5106

Substituting the values we have

z = (0.5106-0.515)/√(0.515(1-0.515)/850)

z = −0.256677

z = −0.257

To determine the p value (test statistic) at 0.10 significance level, using a two tailed hypothesis.

P value = P(Z<-0.257) = 0.797

Since z at 0.10 significance level is between -1.645 and +1.645 and the z score for the test (z = -0.257) which falls with the region bounded by Z at 0.10 significance level. And also the one-tailed hypothesis P-value is 0.797 which is greater than 0.10. Then we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say that at 10% significance level the null hypothesis is valid.

5 0
3 years ago
Lucas paid $16.37 for a T-shirt and $6.33 for a pair of socks.
konstantin123 [22]
He will get back $2.30
5 0
3 years ago
Read 2 more answers
Joshua Treet had a $400.00 average monthly expenditure for entertainment during the second quarter of the year. He spent $401.50
irga5000 [103]
First, the formula for the average of a data set must be defined. It is calculated by adding all the numbers in the data set and then dividing the sum by the number of data. In this case, the average is set to be equal to $400 with the total number of data being 3, with the September expenditure set as an unknown, x. The equation is then set-up to be: 400 = (401.5 + 250 + x)/3. Thus, Joshua can spend as much as $ 548.5 to be able to have the same average as in his second quarter expenditure. 
4 0
3 years ago
If you can buy 1⁄3 of a pound of turkey for 4 dollars, how much can you purchase for 10 dollars? Write your answer as a fraction
gulaghasi [49]
The answer is 5/6 of a pound.
3 0
3 years ago
Read 2 more answers
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