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Digiron [165]
3 years ago
14

Find the perimeter of the figure to the nearest hundredth.

Mathematics
1 answer:
Kobotan [32]3 years ago
7 0

Answer:

65.12 mm

Step-by-step explanation:

Circumference of semicircle = 8π mm

Perimeter = (40 + 8π) = 65.12 mm

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Ten is 5% of what number?
Karo-lina-s [1.5K]

Answer:

200

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Find the product.
Inga [223]
(2p + 7)(3p-9)
2p x 3p= 6p^2
2p x -9= -18p
7 x 3p=21p
7 x -9=-63
6p^2 - 18p + 21p - 63
6p^2 + 3p -63 is the answer.

6 0
3 years ago
Read 2 more answers
Ethan sold 2 3 gallon of lemonade. Kayla sold some lemonade too. Together, they sold 1 1 4 gallons. Who sold more lemonade, Etha
zhenek [66]

Step-by-step explanation:

Ethan sold 2/3 gallon of lemonade.

Kayla sold some lemonade too.

Together they sold 1 1/4 gallons.

Subtract 2/3 from 1 1/4 as follows :

S=1\dfrac{1}{4}-\dfrac{2}{3}\\\\=\dfrac{5}{4}-\dfrac{2}{3}\\\\=\dfrac{7}{12}

So, Kayla sold 7/12 gallons of lemonade.

As 2/3 is more than 7/12, it means Ethan sold more lemonade.

\dfrac{2}{3}-\dfrac{7}{12}=\dfrac{1}{12}

It means Eathn sold 1/12 more lemonade.

5 0
3 years ago
The concentration of particles in a suspension is 50 per mL. A 5 mL volume of the suspension is withdrawn. a. What is the probab
kolezko [41]

Answer:

(a) 0.6579

(b) 0.2961

(c) 0.3108

(d) 240

Step-by-step explanation:

The random variable <em>X</em> can be defined as the number of particles in a suspension.

The concentration of particles in a suspension is 50 per ml.

Then in 5 mL volume of the suspension the number of particles will be,

5 × 50 = 250.

The random variable <em>X</em> thus follows a Poisson distribution with parameter, <em>λ</em> = 250.

The Poisson distribution with parameter λ, can be approximated by the Normal distribution, when λ is large say λ > 10.  

The mean of the approximated distribution of X is:

μ = λ  = 250

The standard deviation of the approximated distribution of X is:

σ = √λ  = √250 = 15.8114

Thus, X\sim N(250, 250)

(a)

Compute the probability that the number of particles withdrawn will be between 235 and 265 as follows:

P(235

                             =P(-0.95

Thus, the value of P (235 < <em>X</em> < 265) = 0.6579.

(b)

Compute the probability that the average number of particles per mL in the withdrawn sample is between 48 and 52 as follows:

P(48

                             =P(-0.28

Thus, the value of P(48.

(c)

A 10 mL sample is withdrawn.

Compute the probability that the average number of particles per mL in the withdrawn sample is between 48 and 52 as follows:

P(48

                             =P(-0.40

Thus, the value of P(48.

(d)

Let the sample size be <em>n</em>.

P(48

                             0.95=P(-z

The value of <em>z</em> for this probability is,

<em>z</em> = 1.96

Compute the value of <em>n</em> as follows:

z=\frac{\bar X-\mu}{\sigma/\sqrt{n}}\\\\1.96=\frac{48-50}{15.8114/\sqrt{n}}\\\\n=[\frac{1.96\times 15.8114}{48-50}]^{2}\\\\n=240.1004\\\\n\approx 241

Thus, the sample selected must be of size 240.

5 0
3 years ago
(<br> x<br> −<br> 3<br> )<br> (<br> x<br> −<br> 1<br> )<br> (x−3)(x−1)
galina1969 [7]

Answer:

x² - 4x + 3

Step-by-step explanation:

When multiplying binomials (two terms in an expression), use FOIL. It stands for the first, outside, inside, and last terms in each bracket.

(x−3)(x−1)           Expand with FOIL

= x² - x - 3x + 3      Collect like terms

= x² - 4x + 3

7 0
3 years ago
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