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sesenic [268]
2 years ago
15

Select the expressions that are polynomials,

Mathematics
1 answer:
soldier1979 [14.2K]2 years ago
3 0

Answer:

A is the correct answer to the question

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How do you solve 7 (6x + 2)?​
Lerok [7]

Answer:

42x + 14​

Step-by-step explanation:

to  solve this type of question , all you have to do is to follow some simple rule of BODMAS

B.............. bracket open

O.............. of

D................ division

M.................multiplication

A................... Addition

S........................... Subtraction.

so we are just going to apply the B

7 (6x + 2)

42x + 14​

4 0
3 years ago
Read 2 more answers
What is the multiplicative inverse of 8? <br> -1/8 <br> 1/8 <br> -8 <br> 0.08
Lemur [1.5K]

Answer: it's 1/8

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
What is the equation when y=5x+4 is reflected over the x-axis, y-axis &amp; y=x?
tigry1 [53]

Answer:

A) y=-5x-4

B) y=-5x+4

C) y=\frac{x-4}{5}

Step-by-step explanation:

So we have the equation:

y=5x+4

Let's write this in function notation. Thus:

y=f(x)=5x+4

A)

To flip a function over the x-axis, multiply the function by -1. Thus:

f(x)=5x+4\\-(f(x))=-(5x+4)

Simplify:

-f(x)=-5x-4

B) To flip a function over the y-axis, change the variable x to -x. Thus:

f(x)=5x+4\\f(-x)=5(-x)+4

Simplify:

f(-x)=-5x+4

C) A reflection over the line y=x is synonymous with finding the inverse of the function.

To find the inverse, switch x and f(x) and solve for f(x):

f(x)=5x+4

Switch:

x=5f^{-1}(x)+4

Subtract 4 from both sides:

x-4=5f^{-1}(x)

Divide both sides by 5:

f^{-1}(x)=\frac{x-4}{5}

And we're done :)

7 0
3 years ago
What is 20% of 120? Select one O O O 20 240​
balandron [24]
20% of 120 can be represented as 120 * 0.20
120 * 0.20 = 24

so 20% of 120 is 24
5 0
3 years ago
Tan(x+pi/2)= negative cot x
DIA [1.3K]
I'm only going to alter the left hand side. The right side will stay the same the entire time

I'll use the identity tan(x) = sin(x)/cos(x) and cot(x) = cos(x)/sin(x)
I'll also use sin(x+y) = sin(x)cos(y)+cos(x)sin(y) and cos(x+y) = cos(x)cos(y)-sin(x)sin(y)

So with that in mind, this is how the steps would look:

tan(x+pi/2) = -cot x
sin(x+pi/2)/cos(x+pi/2) = -cot x
(sin(x)cos(pi/2)+cos(x)sin(pi/2))/(cos(x)cos(pi/2)-sin(x)sin(pi/2)) = -cot x
(sin(x)*0+cos(x)*1)/(cos(x)*0-sin(x)*1) = -cot x
(0+cos(x))/(-sin(x)-0) = -cot x
(cos(x))/(-sin(x)) = -cot x
-cot x = -cot x

Identity is confirmed

6 0
3 years ago
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