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Svetradugi [14.3K]
3 years ago
13

Help me , thank you very much for helping

Mathematics
2 answers:
Maslowich3 years ago
4 0

Answer:

A and D are functions

Step-by-step explanation:

A is a function because each output is going down the same amount each time, in this case, going down by 4. (the function here is y = -x + 11)

B is not a function because there isn't a constant for y.

C isn't a function either because two x's are 0 with different y values, and you can't have that in a function.

D is also a function because of the equation on the right side.

The red line of the attachment below in A's function graphed, and the lime curve represents D's function graphed.

schepotkina [342]3 years ago
3 0
You’re welcome aiuxhdbenkaaourbrnkqiausbde
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If BFD and AFC are right angles and
wlad13 [49]

Answer:

72

Step-by-step explanation:

If BFD is a right angle and it gives you CFD that means that you do 90 - 72 to find CFB cause it 90 all togther

CFB = 18 deg

now it also tells us CFA is a 90 deg angle so we do the same thing

90 - 18 = 72

4 0
3 years ago
Solve the simultaneous equations<br> y = 9 - X<br> y = 2x2 + 4x + 6
kenny6666 [7]

Answer:

\mathrm{Therefore,\:the\:final\:solutions\:for\:}y=9-x,\:y=2x^2+4x+6\mathrm{\:are\:}

\begin{pmatrix}x=\frac{1}{2},\:&y=\frac{17}{2}\\ x=-3,\:&y=12\end{pmatrix}

Step-by-step explanation:

Given the simultaneous equations

y=9-x

y\:=\:2x^2\:+\:4x\:+\:6

Subtract the equations

y=9-x

-

\underline{y=2x^2+4x+6}

y-y=9-x-\left(2x^2+4x+6\right)

\mathrm{Refine}

x\left(2x+5\right)=3

\mathrm{Solve\:}\:x\left(2x+5\right)=3

2x^2+5x=3        ∵ \mathrm{Expand\:}x\left(2x+5\right):\quad 2x^2+5x

\mathrm{Subtract\:}3\mathrm{\:from\:both\:sides}

2x^2+5x-3=3-3

\mathrm{Solve\:with\:the\:quadratic\:formula}

\mathrm{Quadratic\:Equation\:Formula:}

\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}

x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

\mathrm{For\:}\quad a=2,\:b=5,\:c=-3:\quad x_{1,\:2}=\frac{-5\pm \sqrt{5^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}v\\

x=\frac{-5+\sqrt{5^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}

  =\frac{-5+\sqrt{5^2+4\cdot \:2\cdot \:3}}{2\cdot \:2}

  =\frac{-5+\sqrt{49}}{2\cdot \:2}

  =\frac{-5+\sqrt{49}}{4}

  =\frac{-5+7}{4}

  =\frac{2}{4}

  =\frac{1}{2}

Similarly,

x=\frac{-5-\sqrt{5^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}:\quad -3

\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}

x=\frac{1}{2},\:x=-3

\mathrm{Plug\:the\:solutions\:}x=\frac{1}{2},\:x=-3\mathrm{\:into\:}y=9-x

\mathrm{For\:}y=9-x\mathrm{,\:subsitute\:}x\mathrm{\:with\:}\frac{1}{2}:\quad y=\frac{17}{2}

\mathrm{For\:}y=9-x\mathrm{,\:subsitute\:}x\mathrm{\:with\:}-3:\quad y=12

\mathrm{Therefore,\:the\:final\:solutions\:for\:}y=9-x,\:y=2x^2+4x+6\mathrm{\:are\:}

\begin{pmatrix}x=\frac{1}{2},\:&y=\frac{17}{2}\\ x=-3,\:&y=12\end{pmatrix}

3 0
4 years ago
Given the figure below, find the values of x and z.<br> (5x + 86)<br> (10x + 34)<br> X =<br> Z=
kolezko [41]

Answer:

x = 4 \\ z = 106

Step-by-step explanation:

(5x + 86) + (10x + 34) = 180 \\ 15x + 120 = 180 \\ 15x = 180 - 120 \\ 15x = 60 \\  \\ x =  \frac{60}{15}  \\  \\ x = 4

(5x + 86) = 5(4) + 86 = 20 - 86 = 106

Z= 106 —> Opposite angles

I hope I helped you^_^

8 0
3 years ago
X=−4a 2 +3ab+12b 2 Y=9a 2 +ab−7b 2 ​ Y+X=Y+X=Y, plus, X, equals
dimaraw [331]

Answer:

5a  

2

+4ab+5b  

2

Step-by-step explanation:

step  1. (((0-(4•(a2)))+3ab)+(12•(b2)))+(((9•(a2))+ab)-7b2)

 step 2. (((0-(4•(a2)))+3ab)+(12•(b2)))+((32a2+ab)-7b2)

step 3.(((0-(4•(a2)))+3ab)+(22•3b2))+(9a2+ab-7b2)

step 4. (((0-(4•(a2)))+3ab)+(22•3b2))+(9a2+ab-7b2)

step 5. 5.1    Factoring    5a2 + 4ab + 5b2

6 0
4 years ago
How many dollars are in Fifty pennies
andrew11 [14]
1/2. 50 pennies equals $0.50
4 0
4 years ago
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