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3 years ago

Help me , thank you very much for helping

Mathematics

2 answers:

Maslowich3 years ago

4 0

Answer:

A and D are functions

Step-by-step explanation:

A is a function because each output is going down the same amount each time, in this case, going down by 4. (the function here is y = -x + 11)

B is not a function because there isn't a constant for y.

C isn't a function either because two x's are 0 with different y values, and you can't have that in a function.

D is also a function because of the equation on the right side.

The red line of the attachment below in A's function graphed, and the lime curve represents D's function graphed.

schepotkina [342]3 years ago

3 0

You’re welcome aiuxhdbenkaaourbrnkqiausbde

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If BFD and AFC are right angles and

wlad13 [49]

Answer:

Step-by-step explanation:

If BFD is a right angle and it gives you CFD that means that you do 90 - 72 to find CFB cause it 90 all togther

CFB = 18 deg

now it also tells us CFA is a 90 deg angle so we do the same thing

90 - 18 = 72

4 0

3 years ago

Solve the simultaneous equations y = 9 - X y = 2x2 + 4x + 6

kenny6666 [7]

Answer:

$\mathrm{Therefore,\:the\:final\:solutions\:for\:}y=9-x,\:y=2x^2+4x+6\mathrm{\:are\:}$

$\begin{pmatrix}x=\frac{1}{2},\:&y=\frac{17}{2}\\ x=-3,\:&y=12\end{pmatrix}$

Step-by-step explanation:

Given the simultaneous equations

$y=9-x$

$y\:=\:2x^2\:+\:4x\:+\:6$

Subtract the equations

$y=9-x$

$-$

$\underline{y=2x^2+4x+6}$

$y-y=9-x-\left(2x^2+4x+6\right)$

$\mathrm{Refine}$

$x\left(2x+5\right)=3$

$\mathrm{Solve\:}\:x\left(2x+5\right)=3$

$2x^2+5x=3$ ∵ $\mathrm{Expand\:}x\left(2x+5\right):\quad 2x^2+5x$

$\mathrm{Subtract\:}3\mathrm{\:from\:both\:sides}$

$2x^2+5x-3=3-3$

$\mathrm{Solve\:with\:the\:quadratic\:formula}$

$\mathrm{Quadratic\:Equation\:Formula:}$

$\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}$

$x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\mathrm{For\:}\quad a=2,\:b=5,\:c=-3:\quad x_{1,\:2}=\frac{-5\pm \sqrt{5^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}v\\$

$x=\frac{-5+\sqrt{5^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}$

$=\frac{-5+\sqrt{5^2+4\cdot \:2\cdot \:3}}{2\cdot \:2}$

$=\frac{-5+\sqrt{49}}{2\cdot \:2}$

$=\frac{-5+\sqrt{49}}{4}$

$=\frac{-5+7}{4}$

$=\frac{2}{4}$

$=\frac{1}{2}$

Similarly,

$x=\frac{-5-\sqrt{5^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}:\quad -3$

$\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}$

$x=\frac{1}{2},\:x=-3$

$\mathrm{Plug\:the\:solutions\:}x=\frac{1}{2},\:x=-3\mathrm{\:into\:}y=9-x$

$\mathrm{For\:}y=9-x\mathrm{,\:subsitute\:}x\mathrm{\:with\:}\frac{1}{2}:\quad y=\frac{17}{2}$

$\mathrm{For\:}y=9-x\mathrm{,\:subsitute\:}x\mathrm{\:with\:}-3:\quad y=12$

$\mathrm{Therefore,\:the\:final\:solutions\:for\:}y=9-x,\:y=2x^2+4x+6\mathrm{\:are\:}$

$\begin{pmatrix}x=\frac{1}{2},\:&y=\frac{17}{2}\\ x=-3,\:&y=12\end{pmatrix}$

3 0

4 years ago

Given the figure below, find the values of x and z. (5x + 86) (10x + 34) X = Z=

kolezko [41]

Answer:

$x = 4 \\ z = 106$

Step-by-step explanation:

$(5x + 86) + (10x + 34) = 180 \\ 15x + 120 = 180 \\ 15x = 180 - 120 \\ 15x = 60 \\ \\ x = \frac{60}{15} \\ \\ x = 4$

$(5x + 86) = 5(4) + 86 = 20 - 86 = 106$

Z= 106 —> Opposite angles

I hope I helped you^_^

8 0

3 years ago

X=−4a 2 +3ab+12b 2 Y=9a 2 +ab−7b 2 Y+X=Y+X=Y, plus, X, equals

dimaraw [331]

Answer:

+4ab+5b

Step-by-step explanation:

step 1. (((0-(4•(a2)))+3ab)+(12•(b2)))+(((9•(a2))+ab)-7b2)

step 2. (((0-(4•(a2)))+3ab)+(12•(b2)))+((32a2+ab)-7b2)

step 3.(((0-(4•(a2)))+3ab)+(22•3b2))+(9a2+ab-7b2)

step 4. (((0-(4•(a2)))+3ab)+(22•3b2))+(9a2+ab-7b2)

step 5. 5.1 Factoring 5a2 + 4ab + 5b2

6 0

4 years ago

How many dollars are in Fifty pennies

andrew11 [14]

1/2. 50 pennies equals $0.50

4 0

4 years ago

Read 2 more answers