All categories

2 years ago

A customer paid $12.50 for 3 pounds of cheese. At the same rate, how much would 2 pounds of cheese cost?

Mathematics

1 answer:

andrew-mc [135]2 years ago

3 0

Answer:

8.333 repeat

Step-by-step explanation:

12.50÷3=4.166 repeat

take that and do 4.166 repeat×2 and thats hiw you get your answer

You might be interested in

What is triangle ABC ? (line segments)

Bess [88]

Triangle ABD and ADC are righttriangles so u can use the Pythagorean theorem/triples. the triples are 3/4/5 and 5/12/13. 12 is 4x3, and 15 is 5x3, so BD is 3x3, which is 9. AC is 13, as it is part of the Pythagorean’s triples

7 0

3 years ago

A square pyramid has a height of 6 units and a volume of 70 units? If a square prism has the same base area and volume as the sq

Slav-nsk [51]

Answer:

2 units

Step-by-step explanation:

Vpyramid = ⅓ x base area x height

70 = ⅓ x base area x 6

70 = 2 x base area

base area = 70/2 = 35 units

Vprism = base area x height

70 = 35 x height

height = 70/35 = 2 Units

5 0

3 years ago

Read 2 more answers

Where are three places you might find line segments in the real world?

egoroff_w [7]

Answer:

Real-world examples of line segments are a pencil, a baseball bat, the cord to your cell phone charger, the edge of a table, etc. Think of a real-life quadrilateral, like a chessboard; it is made of four line segments

Step-by-step explanation:

Hope this helps:)

5 0

3 years ago

Water is drained out of tank, shaped as an inverted right circular cone that has a radius of 4cm and a height of 16cm, at the ra

bearhunter [10]

Answer:

$\frac{dh}{dt}=-\frac{1}{2\pi}cm/min$

Step-by-step explanation:

From similar triangles, see diagram in attachment

$\frac{r}{4}=\frac{h}{16}$

We solve for $r$ to obtain,

$r=\frac{h}{4}$

The formula for calculating the volume of a cone is

$V=\frac{1}{3}\pi r^2h$

We substitute the value of $r=\frac{h}{4}$ to obtain,

$V=\frac{1}{3}\pi (\frac{h}{4})^2h$

This implies that,

$V=\frac{1}{48}\pi h^3$

We now differentiate both sides with respect to $t$ to get,

$\frac{dV}{dt}=\frac{\pi}{16}h^2 \frac{dh}{dt}$

We were given that water is drained out of the tank at a rate of $2cm^3/min$

This implies that $\frac{dV}{dt}=-2cm^3/min$ .

Since we want to determine the rate at which the depth of the water is changing at the instance when the water in the tank is 8cm deep, it means $h=8cm$ .