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musickatia [10]
3 years ago
11

What is the value of x ? round your answer to the nearest tenth .

Mathematics
1 answer:
djverab [1.8K]3 years ago
4 0

Answer:

39 maybe i don't know

Step-by-step explanation:

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The sum of twice a number and 15 is grater the 3
NNADVOKAT [17]

Answer:

x>-6

Step-by-step explanation:

The expression you need to solve for this is: 2x+15>3

For now pretend that the > is a = and solve as you normally would for x.

Subtract 15 from both sides

2x=-12

Divide by 2

x=-6

Put the > back in

x>-6

4 0
2 years ago
Assume that you have a sample of n 1 equals 6​, with the sample mean Upper X overbar 1 equals 50​, and a sample standard deviati
tigry1 [53]

Answer:

t=\frac{(50 -38)-(0)}{7.46\sqrt{\frac{1}{6}+\frac{1}{5}}}=2.656

df=6+5-2=9

p_v =P(t_{9}>2.656) =0.0131

Since the p value is higher than the significance level given of 0.01 we don't have enough evidence to conclude that the true mean for group 1 is significantly higher thn the true mean for the group 2.

Step-by-step explanation:

Data given

n_1 =6 represent the sample size for group 1

n_2 =5 represent the sample size for group 2

\bar X_1 =50 represent the sample mean for the group 1

\bar X_2 =38 represent the sample mean for the group 2

s_1=7 represent the sample standard deviation for group 1

s_2=8 represent the sample standard deviation for group 2

System of hypothesis

The system of hypothesis on this case are:

Null hypothesis: \mu_1 \leq \mu_2

Alternative hypothesis: \mu_1 > \mu_2

We are assuming that the population variances for each group are the same

\sigma^2_1 =\sigma^2_2 =\sigma^2

The statistic for this case is given by:

t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}

The pooled variance is:

S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}

We can find the pooled variance:

S^2_p =\frac{(6-1)(7)^2 +(5 -1)(8)^2}{6 +5 -2}=55.67

And the pooled deviation is:

S_p=7.46

The statistic is given by:

t=\frac{(50 -38)-(0)}{7.46\sqrt{\frac{1}{6}+\frac{1}{5}}}=2.656

The degrees of freedom are given by:

df=6+5-2=9

The p value is given by:

p_v =P(t_{9}>2.656) =0.0131

Since the p value is higher than the significance level given of 0.01 we don't have enough evidence to conclude that the true mean for group 1 is significantly higher thn the true mean for the group 2.

4 0
3 years ago
Stacey had 3 cakes for her party, She had 1/8 of a cake left after the party. How much cake was eaten at her party?​
hoa [83]

Answer: 3=24/8 24/8 - 1/8 = 23/8 or 2 7/8

Step-by-step explanation:

Exchange 3 into 24/8 which is still 3 but in 8th’s. Then subtract 1/8 from 24/8 which is 23/8 or 2 7/8

8 0
2 years ago
Read 2 more answers
2√72÷√8±√2<br><br> I Need help with this question fast
Oxana [17]

2√72 / √8 ± √2

If the denominator is √8 + √2,

2√72 / √8 + √2

= 2√(2*2*2*3*3) / √(2*2*2) + √2

= 2*2*3√2 / 2√2 + √2

= 12√2 / 3√2

= 4

4 0
3 years ago
Let T: Mmxn(R)Mmxn(R) be the function defined
alexandr402 [8]

Answer:

True. See the explanation and proof below.

Step-by-step explanation:

For this case we need to remeber the definition of linear transformation.

Let A and B be vector spaces with same scalars. A map defined as T: A >B is called a linear transformation from A to B if satisfy these two conditions:

1) T(x+y) = T(x) + T(y)

2) T(cv) = cT(v)

For all vectors x,y \in V and for all scalars c \in R. And A is called the domain and B the codomain of T.

Proof

For this case the tranformation proposed is t: M_{mxn} (R) > M_{nxm} (R)

Where T(A) = A^T

For this case we have the following assumption:

1) The transpose of an nxm matrix is an nxm matrix

And the following conditions:

2) T(A+B) = (A+B)^T = A^T + B^T = T(A) + T(B)

And we can express like this T(A+B) =T(A) + T(B)

3) If A \in M_{mxn}(R) and c \in R then we have this:

T(cA) = (cA)^T = cA^T = cT(A)

And since we have all the conditions satisfied, we can conclude that T is a linear transformation on this case.

5 0
3 years ago
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