Solve: 5n = 25 A. n = 8 B. n = 5 C. n = 2 D. n = 1
2 answers:
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The question is missing parts. Here is the complete question.
Find the absolute maximum and absolute minimum values of f on the given interval.
, [ -2,8]
Answer: Absolute maximum: f(4) = 2.42;
Absolute minimum: f(-2) = -1.76;
Step-by-step explanation: Some functions have absolute extrema: maxima and/or minima.
<u>Absolute</u> <u>maximum</u> is a point where the function has its greatest possible value.
<u>Absolute</u> <u>minimum</u> is a point where the function has its least possible value.
The method for finding absolute extrema points is
1) Derivate the function;
2) Find the values of x that makes f'(x) = 0;
3) Using the interval boundary values and the x found above, determine the function value of each of those points;
4) The highest value is maximum, while the lowest value is minimum;
For the function given, absolute maximum and minimum points are:
Using the product rule, first derivative will be:
= 0
x = ±4
x can't be -4 because it is not in the interval [-2,8].
Analysing each f(x), we noted when x = -2, f(-2) is minimum and when x = 4, f(4) is maximum.
Therefore, absolute maximum is f(4) = 2.42 and
absolute minimum is f(-2) = -1.76
Hey there!
You got the first part right where you added r to both sides. However, you need to make sure that you complete all actions on both sides, including canceling out parts of terms by division. The only thing you need to do is divide both sides by h instead of just the left. This will make your answer:
Hope this helped you out! :-)
You got the first part right where you added r to both sides. However, you need to make sure that you complete all actions on both sides, including canceling out parts of terms by division. The only thing you need to do is divide both sides by h instead of just the left. This will make your answer:
Hope this helped you out! :-)