Answer:
Step-by-step explanation:
Like terms have same variable with same power. Combine like terms
153y³ + 132y² + 6y - 5 - 3y³ - 5y² +4y - 2
= <u>153y³ - 3y³</u> + 132y² - 5y² + 6y + 4y <u> -5 - 2</u>
= <u>150y³</u> + 127y² + 10y<u> - 7</u>
C. 8.7 x 102
8.7 x 102= 887.4
Which is the largest product out of all the other equations.
Hope this helps!
<u>We are given:</u>
An even number 'n', multiplied by the next consecutive even number is 168
<u>Solving for n:</u>
From the given statement, we can say that:
n(n+2) = 168 [<em>n multiplied by the next even number 'n+2'</em>]
n² + 2n = 168
n² + 2n - 168 = 0 [<em>subtracting 168 from both sides</em>]
We can see that we now have a quadratic equation, solving using splitting the middle term
n² + 14n - 12n - 168 = 0
n(n + 14) -12(n + 14) = 0 <em>[factoring out common terms</em>]
(n-12)(n+14) = 0
Here, we can divide both sides by either (n-12) OR (n+14)
Checking the result in both the cases:
(n + 14) = 0/(n-12) (n-12) = 0/(n+14)
n + 14 = 0 n - 12 = 0
n = -14 n = 12
Both these values are even and since we are not told if the number 'n' is positive or negative, both 12 and -14 are the possible values of n
Answer:
see attached
Step-by-step explanation:
The infinite series with a common ratio greater than 1 will not have a finite sum.
Subtracting a value from the input x shifts the graph that number of units to the right.
The answer would be C.
