Answer:
class boundaries are the end points of an open interval which contains the class interval such that the lower class boundary (LCB) is the LCL minus one-half the tolerance and the upper class boundary (UCB) is the UCL plus one -half the tolerance.
I don't know what you mean by unknown factor but a quotient is the answer of a division problem
I put the solution on the paper
Sense we are wanting to find <u>
how many were miss</u>
, then, we are practically going to subtract the following:
![\boxed{76-100}= \ \left[\begin{array}{ccc}\bf{24\end{array}\right]](https://tex.z-dn.net/?f=%5Cboxed%7B76-100%7D%3D%20%5C%20%20%20%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%5Cbf%7B24%5Cend%7Barray%7D%5Cright%5D%20)
So, from this begin understood, we would then combine both the penalties that were shotted, to the onces that weren't.
So, b subtracting these both, we would grab the result, and then smash that with the number of the penalties that were made in.
Your answer:
Okay! Let's write out all the numbers:
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
Now, let's bold (or you can circle them... or do really anything to them as long as they are standing out to you) the even numbers (remember all even numbers are divisible by 2)
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
Now let's list all the ones we highlighted:
2
4
6
8
10
12
14
Count up how many numbers that is.
You should get 7.
So, our answer is 7 out of 15 numbers.
Or as a fraction:
7/15 is our answer.
Note: A probability is the number of chances something has to happen out of the total number of chances. So in this case the number of even numbers out of the total number of numbers. You can apply this to any probability problem. Hope this helps!
Read more on Brainly.com - brainly.com/question/2150566#readmore