Y² - 12y + 32
The middle term must be written in such a way that the sum of two numbers is -12y and the product is 32y²
The two such numbers are -4y and -8y
So, we can write:
y² - 4y - 8y + 32
= y(y - 4) - 8(y - 4)
= (y - 4)(y - 8)
So, option B gives the correct answer
Answer:
Point of intersection:

2 × equation(b) + equation (a):

Point of intersection = (3, 1)
Perpendicular line:

General equation of line:

<u>Value</u><u> </u><u>of</u><u> </u><u>m</u><u>:</u>
<u>
</u>
First, we pass the other number subtracting, like this:

Then we pass the number 3 dividing, like this:

So, the answer is: W = -3.
Hope this helped! c:
Here is an example f(x)X squared minus 6x plus five
Answer:
C
Step-by-step explanation:
39*34= 1326 (the area of the full square
8*10=80 (the area of the small square that is cut off)
1326-80= 1246