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son4ous [18]
2 years ago
12

HELPP ASAP I’ll MARK YOu AS brainlister:(!!!

Mathematics
1 answer:
Lorico [155]2 years ago
7 0

Answer:

69

Step-by-step

edp445

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Answer:

0.875 as a decimal
875/1000 or 7/8 as a fraction

explanation:

7/8 = 0.875
875/1000 = 0.875

hope this helps :)
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The weights of laboratory cockroaches follow a normal distribution with mean 80 grams and standard deviation 2 grams. about what
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If A = {2, 4, 6, 8, 10} and B = {1, 2, 3, 4, 5}, find A Intersects with B.
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8 0
2 years ago
Considering only the values of β for which sinβtanβsecβcotβ is defined, which of the following expressions is equivalent to sinβ
-Dominant- [34]

Answer:

\tan(\beta)

Step-by-step explanation:

For many of these identities, it is helpful to convert everything to sine and cosine, see what cancels, and then work to build out to something.  If you have options that you're building toward, aim toward one of them.

{\tan(\theta)}={\dfrac{\sin(\theta)}{\cos(\theta)}    and   {\sec(\theta)}={\dfrac{1}{\cos(\theta)}

Recall the following reciprocal identity:

\cot(\theta)=\dfrac{1}{\tan(\theta)}=\dfrac{1}{ \left ( \dfrac{\sin(\theta)}{\cos(\theta)} \right )} =\dfrac{\cos(\theta)}{\sin(\theta)}

So, the original expression can be written in terms of only sines and cosines:

\sin(\beta)\tan(\beta)\sec(\beta)\cot(\beta)

\sin(\beta) * \dfrac{\sin(\beta) }{\cos(\beta) } * \dfrac{1 }{\cos(\beta) } * \dfrac{\cos(\beta) } {\sin(\beta) }

\sin(\beta) * \dfrac{\sin(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}}{\cos(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}} * \dfrac{1 }{\cos(\beta) } * \dfrac{\cos(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}} {\sin(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}}

\sin(\beta) *\dfrac{1 }{\cos(\beta) }

\dfrac{\sin(\beta)}{\cos(\beta) }

Working toward one of the answers provided, this is the tangent function.


The one caveat is that the original expression also was undefined for values of beta that caused the sine function to be zero, whereas this simplified function is only undefined for values of beta where the cosine is equal to zero.  However, the questions states that we are only considering values for which the original expression is defined, so, excluding those values of beta, the original expression is equivalent to \tan(\beta).

8 0
2 years ago
If YU= YV ST=16 mQS=34 and mRT=98 find each measure will mark brainliest
aksik [14]

Answer:

QR=8

QU=76

Measure of arc ST=114°

Measure of arc QR=114°

Measure of arc XT=57°

Step-by-step explanation:

Given

YU=YV

ST=16

mQS=34

mRT=98

Using Pythagoras theorem,

QR=8

QU=76

QR=ST

So they both span the same arc.

Let the arc=x

360 - QS - RT = QR + ST

Recall QR=ST

360 - 34 - 98 = x + x

228 = 2x

X=228/2

X=114°

Therefore, measure of arc ST and arc QR=114° each

Measure of the span of arc XT = (1/2) of (arc ST)

= (1/2)(114°)

= 57°

8 0
3 years ago
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