Answer:
-1
Step-by-step explanation:
The expression evaluates to the indeterminate form -∞/∞, so L'Hopital's rule is appropriately applied. We assume this is the common log.
d(log(x))/dx = 1/(x·ln(10))
d(log(cot(x)))/dx = 1/(cot(x)·ln(10)·(-csc²(x)) = -1/(sin(x)·cos(x)·ln(10))
Then the ratio of these derivatives is ...
lim = -sin(x)cos(x)·ln(10)/(x·ln(10)) = -sin(x)cos(x)/x
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At x=0, this has the indeterminate form 0/0, so L'Hopital's rule can be applied again.
d(-sin(x)cos(x))/dx = -cos(2x)
dx/dx = 1
so the limit is ...
lim = -cos(2x)/1
lim = -1 when evaluated at x=0.
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I find it useful to use a graphing calculator to give an estimate of the limit of an indeterminate form.
Given:
The ratio of the area between a small square of land and a large square
of land is 3: 7.
Total area of the two squares of land (in sq. meter) is 4000.
Required:
The area of each square of land.
Answer:
We have the ratio of the area between a small square of land and a large square of land is 3: 7.
Let
be the area of the square of land.
Then their ratio is given by,
Also given that the total area of the two squares of land (in sq.meter) is
4,000.
The area of
Therefore,
Therefore,the area of small square (in sq. meter) is,
and the area of large square (in sq. meter) is,
Final Answer:
The area of small and large square respectively (in sq. meter) is,1200 and 2800.
Answer:
a - neither b - perpendicular
Step-by-step explanation:
put them in desmos and look at the lines
Answer:
possible answers are shown in picture.
Step-by-step explanation:
-8.66667266 is the answer to you question.
