Answer:
(1 cm)cos3πt
Step-by-step explanation:
Since the piston starts at its maximal height and returns to its maximal height three times evert 2 seconds, it is modelled by a cosine functions, since a cosine function starts at its maximum point. So, its height h = Acos2πft
where A = amplitude of the oscillation and f = frequency of oscillation and t = time of propagation of oscillation.
Now, since the piston rises in such a way that it returns to the maximal height three times every two seconds, its frequency, f = number of oscillations/time taken for oscillation where number of oscillations = 3 and time taken for oscillations = 2 s
So, f = 3/2 s =1.5 /s = 1.5 Hz
Also, since the the piston moves between 3 cm and 5 cm, the distance between its maximum displacement(crest) of 5 cm and minimum displacement(trough) of 3 cm is H = 5 cm - 3 cm = 2 cm. So its amplitude, A = H/2 = 2 cm/2 = 1 cm
h = Acos2πft
= (1 cm)cos2π(1.5Hz)t
= (1 cm)cos3πt
<span>2x squared - 5
= 2(x)^2 - 5
= 2(4)^2 - 5
= 2(16) - 5
= 32 - 5
= 27</span>
Answer:
2x + 2y = 24
Step-by-step explanation:
Answer:
x1 = 6 + 2√6 or x2 = 6 - 2√6
Step-by-step explanation:
x² - 12x + 12 = 0
We need to use formula:
a² - 2ab + b² = (a - b)².
x² - 12x = - 12
x² - 2*6x + 6²- 6² = - 12
(x - 6)² - 36 = -12
(x - 6)² = - 12 + 36
(x -6)² = 24
(x - 6) = √24 or (x-6) = -√24
(x - 6) = 2√6 or (x-6) = - 2√6
x = 6 + 2√6 or x = 6 - 2√6
