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GREYUIT [131]
3 years ago
7

Please someone help me!

Mathematics
1 answer:
irina1246 [14]3 years ago
3 0

Answer:

B

Step-by-step explanation:

The slope is -2/5x therefore plug in x and then add that to your y

your y right now is -1 as thats where x=0 is

the equation of this line is y= -2/5x -1

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The net weight of milk powder in one medium-size Nido milk tin is 900 grams. Find the weight in grams of milk powder in 15 tins​
ziro4ka [17]

Answer:

13500\ grams

Step-by-step explanation:

Given,\\\\milk\ powder\ in\ one\ medium\ size\ milk\ tin=900\ grams\\\\Then\ in\  15\ tins\ weight\ of\ milk\ powder=total\ number\ of\ tins\times weight\ in\ 1\ tin\\\\In\  15\ tins\ weight\ of\ milk\ powder=15\times 900\\\\In\  15\ tins\ weight\ of\ milk\ powder=13500\ grams

7 0
3 years ago
Read 2 more answers
Isaac drinks 8 glasses of water each day he say he will drink 2,290 glasses of water in 365 is the answer reasonable
svet-max [94.6K]
The answer is not reasonable, Because if he drank that much he would get contaminated and if you multiply 365 by 8 u get 2,920 not 2,290.. but at the same time is reasonable
5 0
3 years ago
The length of a rectangular picture is 17 inches and the perimeter is 60 inches. find the width
Mice21 [21]
I got 255.

Perimeter= 60
60/4=15
15*17=255
8 0
3 years ago
The equation y = 14x represents the number of pages Printer A can print over time, where y is the number of pages and x is time
mr Goodwill [35]
Printer A :
y = 14x......14 pgs per minute

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4 0
3 years ago
A new security system needs to be evaluated in the airport. The probability of a person being a security hazard is 4%. At the ch
ivolga24 [154]

Answer:

(a) 0.9412

(b) 0.9996 ≈ 1

Step-by-step explanation:

Denote the events a follows:

P = a person passes the security system

H = a person is a security hazard

Given:

P (H) = 0.04,\ P(P^{c}|H^{c})=0.02\ and\ P(P|H)=0.01

Then,

P(H^{c})=1-P(H)=1-0.04=0.96\\P(P|H^{c})=1-P(P|H)=1-0.02=0.98\\

(a)

Compute the probability that a person passes the security system using the total probability rule as follows:

The total probability rule states that: P(A)=P(A|B)P(B)+P(A|B^{c})P(B^{c})

The value of P (P) is:

P(P)=P(P|H)P(H)+P(P|H^{c})P(H^{c})\\=(0.01\times0.04)+(0.98\times0.96)\\=0.9412

Thus, the probability that a person passes the security system is 0.9412.

(b)

Compute the probability that a person who passes through the system is without any security problems as follows:

P(H^{c}|P)=\frac{P(P|H^{c})P(H^{c})}{P(P)} \\=\frac{0.98\times0.96}{0.9412} \\=0.9996\\\approx1

Thus, the probability that a person who passes through the system is without any security problems is approximately 1.

7 0
3 years ago
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