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Musya8 [376]
3 years ago
6

What is the value of the expression x^2y–y+xy^2–x for x=4 and y=0.25?

Mathematics
1 answer:
stepan [7]3 years ago
8 0

Answer:

0 (zero)

Step-by-step explanation:

{x}^{2} y - y + x {y}^{2}  - x  \\  =  {4}^{2} \times  0.25 - 0.25 + 4 \times  {0.25}^{2}  - 4 \\  = 16 \times  0.25 - 0.25 + 4 \times  0.0625- 4  \\  = 4 - 0.25 + 0.25 - 4 \\  = 0 \\  \\  \purple {\boxed{ \bold{ \therefore \:  {x}^{2} y - y + x {y}^{2}  - x  = 0}}}

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The product of a number and -3, increased by 8, is 20
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3 years ago
Find the equation of the line parallel to y=2x+1 that contains point (14,3)
Sophie [7]

First of all, remember what the equation of a line is:

y=mx+b

Where: 

m=slope

b=y-intercept.

Given this information, we can start by plugging in what we know, we are given the slope which is 2 so we can fill that in, remember m=slope

y=2x+b

To find b, think about what your (x,y) point means:<span>(14,3). When x of the line is 14, y of the line must be 3.

Because we were given the point (14,3) 
</span>

We need to find the value of b.  The 2 is already set and x and y are variables. We want the equation for the line that specifically passes through the given point (14,3).

<span>Plug in for x the number 14 and for y the number 3:
</span>(14,3).
 y=mx+b or 3=2 × 14+b,

solving for b: b=3-(2)(14). b=-25.

<span>Plug that in for b: 
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<span>Final answer: 
</span><span>y=2x-25</span></span><span><span>
</span></span>
8 0
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