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2 years ago

EXPERT HELP I'LL GIVE BRAINLIEST: EXPLAIN THE ANSWER

Mathematics

2 answers:

tensa zangetsu [6.8K]2 years ago

7 0

Answer:

i think its C

Step-by-step explanation:

its the one that makes sense to me.

goblinko [34]2 years ago

3 0

I think it’s D but I’m not sure

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Find the two missing terms of the sequence and determine if the sequence is arithmetic, geometric, or neither.

wolverine [178]

-5, -7
The sequence is arithmetic.

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2 years ago

What are the solutions to (m +11)2 = 64?

mel-nik [20]

Answer:

(21 + 11)2 = 64

So, I don't think teachers do this, but this is my way of doing it

Okay, so first, I divided 64 by 2 :

64 ÷ 2 = 32

Then, I subtracted 11 from 32:

Now, to check, just do the problem :

(21 + 11)2 = 64

32 * 2 = 64

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2 years ago

Read 2 more answers

What quadrilateral is this?

Kryger [21]

Answer: i think a

Pentagon

Step-by-step explanation:

if not im super sorry

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2 years ago

Express in the form 1:n give n as a decimal 8:6

photoshop1234 [79]

Answer: 8.6:8.6

Explanation:

1:n is the form you want.

n is 8.6. change the n value so it is 1:8.6

1 is 1 times bigger than 8.6

8.6 times 1 is 8.6

so you've got 8.6:8.6

your welcome, i hope this helps

3 0

2 years ago

A quality control expert at Glotech computers wants to test their new monitors. The production manager claims they have a mean l

tankabanditka [31]

Answer:

The probability that the mean monitor life would be greater than 96.3 months in a sample of 84 monitors

P(X⁻ ≥ 96.3) = 0.0087

Step-by-step explanation:

Step(i):-

Given that the mean of the Population = 95

Given that the standard deviation of the Population = 5

Let 'X' be the random variable in a normal distribution

Let X⁻ = 96.3

Given that the size 'n' = 84 monitors

Step(ii):-

The Empirical rule

$Z = \frac{x^{-} -mean}{\frac{S.D}{\sqrt{n} } }$

$Z = \frac{96.3 - 95}{\frac{5}{\sqrt{84} } }$

Z = 2.383

The probability that the mean monitor life would be greater than 96.3 months in a sample of 84 monitors

P(X⁻ ≥ 96.3) = P(Z≥2.383)

= 1- P( Z<2.383)

= 1-( 0.5 -+A(2.38))

= 0.5 - A(2.38)

= 0.5 -0.4913

= 0.0087

Final answer:-

The probability that the mean monitor life would be greater than 96.3 months in a sample of 84 monitors

P(X⁻ ≥ 96.3) = 0.0087

3 0

2 years ago