If you list out the factors of each number, it would look something like this:
36: 1,2,3,4,6,9,12,18,36
40: 1,2,4,5,8,10,20,40
In this case, the GCF of both numbers would be 4
Step-by-step explanation: x
2
−
5
x
+
6 using the AC method.
x
3
+
4
x
2
−
4
x
+
46
(
x
−3
)
(
x
−
2
)
579/3 fist you divid 5 by 3 than you subtract them and get two than you bring down your seven and have 27 divided by 3 and that is 9. than you bring down your last number and than you come up with an answer of 193.
Answer:
(32/5, -48/5)
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality<u>
</u>
<u>Algebra I</u>
- Terms/Coefficients
- Coordinates (x, y)
- Solving systems of equations using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define Systems</u>
-4x + 16 = y
2x - 32 = 2y
<u>Step 2: Solve for </u><em><u>x</u></em>
<em>Substitution</em>
- Substitute in <em>y</em>: 2x - 32 = 2(-4x + 16)
- Distribute 2: 2x - 32 = -8x + 32
- [Addition Property of Equality] Add 8x on both sides: 10x - 32 = 32
- [Addition Property of Equality] Add 32 on both sides: 10x = 64
- [Division Property of Equality] Divide 10 on both sides: x = 32/5
<u>Step 3: Solve for </u><em><u>y</u></em>
- Define original equation: -4x + 16 = y
- Substitute in <em>x</em>: -4(32/5) + 16 = y
- Multiply: -128/5 + 16 = y
- Add: -48/5 = y
- Rewrite/Rearrange: y = -48/5
