In how many ways can the first 4 guests arrive at a party if 15 guests have been invited.
2 answers:
Answer:
the first 4 guests can arrive in 32,760 ways.
Step-by-step explanation:
how many ways can the first 4 guests arrive at a party if 15 guests have been invited.
Permutations formula:
The number of possible permutations of x elements from a set of n elements is given by the following formula:
4 guests from a set of 15
P(15,4) = 15 * 14 * 13 * 12
= 32760
Therefore, the first 4 guests can arrive in 32,760 ways.
Answer:
The first 4 guests can arrive in 32,760 ways.
Step-by-step explanation:
The order in which the guests arrive is important. For example, A,B,C,D is a different outcome to B,A,C,D. So we use the permutations formula to solve this question.
Permutations formula:
The number of possible permutations of x elements from a set of n elements is given by the following formula:
In this question:
4 guests from a set of 15. So
The first 4 guests can arrive in 32,760 ways.
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Answer:
sand = 3450 pounds
3/4 inch stones =6750 pounds
1 inch stones =4800 pounds.
Step-by-step explanation:
The mixture composition is :
45% three-quarter inch stones
32% inch stones and
sand for balance
The percent here is by mass of material used.
Weight of mixture is 15,000 pounds before oil addition.
Use the percent by weight for the two types of stones and calculate real values in pounds
Formula to apply is:
Mass percent = (mass of a material/ total mass of mixture) * 100
For 3/4 inch stones it will be:
The 3/4 inch stones weigh 6750 pounds
The 1 inch stones will be
The 1 inch stones weigh = 4800 pounds
Total for the two items : 4800+6750 =11550 pounds
The sand used weighs : 15000 - 11550 = 3450 pounds