In how many ways can the first 4 guests arrive at a party if 15 guests have been invited.

Mathematics

2 answers:

hichkok12 [17]4 years ago

7 0

Answer:

the first 4 guests can arrive in 32,760 ways.

Step-by-step explanation:

how many ways can the first 4 guests arrive at a party if 15 guests have been invited.

Permutations formula:

The number of possible permutations of x elements from a set of n elements is given by the following formula:

$P_{(n,x)} = \frac{n!}{(n-x)!}$

4 guests from a set of 15

P(15,4) = 15 * 14 * 13 * 12

= 32760

Therefore, the first 4 guests can arrive in 32,760 ways.

notsponge [240]4 years ago

6 0

Answer:

The first 4 guests can arrive in 32,760 ways.

Step-by-step explanation:

The order in which the guests arrive is important. For example, A,B,C,D is a different outcome to B,A,C,D. So we use the permutations formula to solve this question.

Permutations formula:

The number of possible permutations of x elements from a set of n elements is given by the following formula:

$P_{(n,x)} = \frac{n!}{(n-x)!}$

In this question:

4 guests from a set of 15. So

$P_{(15,4)} = \frac{15!}{(15-4)!} = 32760$

The first 4 guests can arrive in 32,760 ways.

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