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12345 [234]
2 years ago
9

A store is Jada's neighborhood sells boxes of pencils that have 6 pencils in each box. Jada bought several boxes of pencils at t

he store. Which could be the number of pencils she bought?
Mathematics
1 answer:
AlexFokin [52]2 years ago
5 0

Answer:

The explanation is given below:

Step-by-step explanation:

The computation of the number of pencils she bought is shown below:

It could be

6 × 2 boxes = 12

6 × 3 boxes = 18

6 × 4 boxes  = 24

6 × 5 boxes = 30

6 × 6 boxes = 36

And so on

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Simplify 14 to the 15th power over 14 to the 5th power
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Answer:

d) 14^10.

Step-by-step explanation:

14^15 / 14^5

= 14^(15-5(

= 14^10.

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Multiply the following polynomials <br><br> A. (2x+1)(3x-2) B. (x+5)(x-5) C. (4x-3)(x^2+3x+2)
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Calculate the value of the following determinants: | 1 -1 3 2 5 0 -3 1 2 | and | -1 -8 2 9 1 0 4 1 2 |
vitfil [10]

Answer:

1) The determinant = 65

2) The determinant = 152

Step-by-step explanation:

Let us show how to find the determinant of a matrix

You can find the determinant of this Matrix  \left[\begin{array}{ccc}a&b&c\\d&e&f\\g&m&n\end{array}\right]

by using this rule

Determinant = a(en - fm) - b(dn - fg) + c(dm - eg)

Let us use this rule with the given matrices

1)

 \left[\begin{array}{ccc}1&-1&3\\2&5&0\\-3&1&2\end{array}\right]

The determinand = 1[(5)(2) - (0)(1)] - (-1)[(2)(2) - (0)(-3)] + 3[(2)(1) - 5(-3)]

= 1[10 - 0] - (-1)[4 - 0] + 3[2 - (-15)]

= 1[10] + 1[4] + 3[2+15]

= 10 + 4 + 3[17]

= 10 + 4 + 51

= 65

The determinant = 65

Let us do the second one

2)

 \left[\begin{array}{ccc}-1&-8&2\\9&1&0\\4&1&2\end{array}\right]

The determinand = -1[(1)(2) - (0)(1)] - (-8)[(9)(2) - (0)(4)] + 2[(9)(1) - 1(4)]

= -1[2 - 0] - (-8)[18 - 0] + 2[9 - 4]

= -1[2] + 8[18] + 2[5]

= -2 + 144 + 10

= 152

The determinant = 152

6 0
3 years ago
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