A triangle has side lengths 7/8 and 3/4. What is the length of the third side, b?

Mathematics

2 answers:

aniked [119]3 years ago

7 0

Answer:

probably 2/4 try it I don't know

AleksAgata [21]3 years ago

6 0

Answer:

1/2

Step-by-step explanation:

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Please help!! In radians, what is the period of the function y = .5cos5x

Levart [38]

Answer:

(2pi)/5

Step-by-step explanation:

The cosine function cos(x) has a period of 2*pi.

If we change the argument of the cosine, the new argument will have a period of 2*pi. If the new argument is 5x, we have that the period will be:

5x = 2*pi

x = 2*pi/5

The period of this function will be (2pi)/5, because for every (2pi)/5 change in the value of x, the function will have the same value. The value of 5 multiplying the cosine does not interfere in the period.

5 0

3 years ago

If F(x)=4x-1 and g(x)=x^2+7, what is g(f(x))

VashaNatasha [74]

Answer

$g(f(x)) = = 16 {x}^{2} - 8x + 8$

step by step Explanation

The functions given are

$f (x)= 4x- 1$

$g(x)= {x}^{2} + 7$

We want to find:

$g(f (x))= g( 4x- 1)$

This implies that

$g(f (x))= ( (4x- 1)^{2} + 7)$

Let us now simplify

$( {a - b)}^{2} = {a}^{2} -2ab + {b}^{2}$

This implies that

$( (4x- 1)^{2} + 7) =( {(4x)}^{2} - 2(4x) \times 1 + 1$

Combine the terms to get,

$= 16 {x}^{2} - 8x + 1 + 7$

$= 16 {x}^{2} - 8x + 8$