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8090 [49]
3 years ago
7

A triangle has side lengths 7/8 and 3/4. What is the length of the third side, b?

Mathematics
2 answers:
aniked [119]3 years ago
7 0

Answer:

probably 2/4 try it I don't know

AleksAgata [21]3 years ago
6 0

Answer:

1/2

Step-by-step explanation:

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take the population mean divided by four

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What is the measure of angle B, m
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70 degrees

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Two rigid transformations are used to map triangle JKL to triangle MNQ. The first is a translation of vertex L to vertex Q. What
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7 0
3 years ago
Read 2 more answers
Algebra 1 question : Solve for x : 3 - 5x + 6 = 14x - 32 + 10(2-x)
Zepler [3.9K]
Hi there!

3 - 5x + 6 = 14x - 32 + 10(2 - x)
Work out the parenthesis.

3 - 5x + 6 = 14x - 32 + 20 - 10x
Combine like terms.

9 - 5x = 4x - 12
Subtract 9 from both sides.

- 5x = 4x - 21
Subtract 4x from both sides

- 9x =  - 21
Divide both sides by -9

x =  \frac{ - 21}{ - 9}  =  \frac{21}{9}  = 2 \frac{3}{9}  = 2 \frac{1}{3}



6 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%20%7B%7D%5E%7B2%7D%20-%204%20%7D%7B%20%5Csqrt%7Bx%20%7B%7D%5E%7B2%7D%20-%206x%2
Nimfa-mama [501]

First of all, we can observe that

x^2-6x+9 = (x-3)^2

So the expression becomes

\dfrac{x^2-4}{\sqrt{(x-3)^2}} = \dfrac{x^2-4}{|x-3|}

This means that the expression is defined for every x\neq 3

Now, since the denominator is always positive (when it exists), the fraction can only be positive if the denominator is also positive: we must ask

x^2-4 \geq 0 \iff x\leq -2 \lor x\geq 2

Since we can't accept 3 as an answer, the actual solution set is

(-\infty,-2] \cup [2,3) \cup (3,\infty)

7 0
2 years ago
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