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3 years ago

If a histogram of a sample of men's ages is skewed, what do you expect to see in the normal quantile plot?

Mathematics

1 answer:

Scorpion4ik [409]3 years ago

5 0

Answer: Points are not following a straight-line pattern

Step-by-step explanation:

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Factorize x^2+3x-ax-3a

Kobotan [32]

Answer:

=−ax+x2−3a+3x

Step-by-step explanation:

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3 years ago

Simplify ^3_/125x^21y^33

Grace [21]

$\sqrt[3]{125x^{21}y^{33}}=\sqrt[3]{125}\cdot\sqrt[3]{x^{21}}\cdot\sqrt[3]{y^{33}}=\sqrt[3]{5^3}\cdot\sqrt[3]{(x^7)^3}\cdot\sqrt[3]{(y^{11})^3}\\\\=\boxed{5x^7y^{11}}\\\\Used:\\\sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\\\\sqrt[n]{a^n}=a\\\\(a^n)^m=a^{nm}$

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3 years ago

May someone please help me with this :)

Luda [366]

So to find the answer you would use the formally 1/2bh
1/2(3.5)(1.5)
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3 years ago

The mean radius of earth is 6,371.0 kilometers and the mean radius of Earth's Moon is 1,737.5 kilometers.What is the approximate

Dmitrij [34]

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3 years ago

you have $15,000 to invest for 5 years at 5.5% annual interest rate that is compounded continuously. how much money will you hav

MissTica

Answer:

$19,747.96

Step-by-step explanation:

You are going to want to use the continuous compound interest formula, which is shown below:

$A = Pe^{rt}$

A = total

P = principal amount

r = interest rate (decimal)

t = time (years)

First, lets change 5.5% into a decimal:

5.5% -> $\frac{5.5}{100}$ -> 0.055

Next, plug in the values into the equation:

$A=15,000e^{0.055(5)}$

$A=19,747.96$

After 5 years, you will have $19,747.96

4 0

3 years ago

If a histogram of a sample of​ men's ages is​ skewed, what do you expect to see in the normal quantile​ plot?

If a histogram of a sample of men's ages is skewed, what do you expect to see in the normal quantile plot?