Answer:
The answer is
Step-by-step explanation:
C................
Given the following table that gives data from a linear function:
![\begin {tabular} {|c|c|c|c|} Temperature, $y = f(x)$ (^\circ C)&0&5&20 \\ [1ex] Temperature, $x$ (^\circ F)&32&41&68 \\ \end {tabular}](https://tex.z-dn.net/?f=%5Cbegin%20%7Btabular%7D%0A%7B%7Cc%7Cc%7Cc%7Cc%7C%7D%0ATemperature%2C%20%24y%20%3D%20f%28x%29%24%20%28%5E%5Ccirc%20C%29%260%265%2620%20%5C%5C%20%5B1ex%5D%0ATemperature%2C%20%24x%24%20%28%5E%5Ccirc%20F%29%2632%2641%2668%20%5C%5C%20%0A%5Cend%20%7Btabular%7D)
The formular for the function can be obtained by choosing two points from the table and using the formular for the equation of a straight line.
Recall that the equation of a straight line is given by

Using the points (32, 0) and (41, 5), we have:
Y - Y2 = M(x-x2)
M = (-3/2) or (3/-2)
Y -(-3) = (-3/2) (X-2)
Y + 3 = (-3/2)(X-2)
14/33 or in decimal form is 0.4242
Look at the picture.
The angle y° and 71° are Supplementary Angles. Therefore y° + 71° = 180°.

The sum of measures of these three angles of any triangle is invariably equal to 180°.
Therefore we have the equation:
