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mart [117]
2 years ago
7

The length of a rectangle is four times the width minus three. If the perimeter of the rectangle is 64 meters, what is the lengt

h?
Mathematics
1 answer:
Nastasia [14]2 years ago
6 0

Answer:

L = 25 m

Step-by-step explanation:

L = 4W - 3

perimeter = 2(L + W)

64 = 2(4W - 3 + W)

divide both sides by 2:

32 = 5W - 3

add 3 to each side:

5W = 35

divide both sides by 5:

W =7

L = 4(7) - 3 = 25

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It equals 10 000
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3 years ago
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A teenager who is 5 feet tall throws an object into the air. The quadratic function LaTeX: f\left(x\right)=-16x^2+64x+5f ( x ) =
tia_tia [17]

Answer:

At approximately x = 0.08 and x = 3.92.

Step-by-step explanation:

The height of the ball is modeled by the function:

f(x)=-16x^2+64x+5

Where f(x) is the height after x seconds.

We want to determine the time(s) when the ball is 10 feet in the air.

Therefore, we will set the function equal to 10 and solve for x:

10=-16x^2+64x+5

Subtracting 10 from both sides:

-16x^2+64x-5=0

For simplicity, divide both sides by -1:

16x^2-64x+5=0

We will use the quadratic formula. In this case a = 16, b = -64, and c = 5. Therefore:

\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

Substitute:

\displaystyle x=\frac{-(-64)\pm\sqrt{(-64)^2-4(16)(5)}}{2(16)}

Evaluate:

\displaystyle x=\frac{64\pm\sqrt{3776}}{32}

Simplify the square root:

\sqrt{3776}=\sqrt{64\cdot 59}=8\sqrt{59}

Therefore:

\displaystyle x=\frac{64\pm8\sqrt{59}}{32}

Simplify:

\displaystyle x=\frac{8\pm\sqrt{59}}{4}

Approximate:

\displaystyle x=\frac{8+\sqrt{59}}{4}\approx 3.92\text{ and } x=\frac{8-\sqrt{59}}{4}\approx0.08

Therefore, the ball will reach a height of 10 feet at approximately x = 0.08 and x = 3.92.

7 0
2 years ago
If the sum of two numbers is 15 and their product is 50 what are they
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Xy = 50
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y^2 - 5y + 50 = 0

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y - 5 = 0 or y - 10 = 0

y = 5 or y = 10

x + y = 15

For y = 5: 

x + 5 = 15

x = 10

For y = 10

x + 10 = 15

x = 5

Answer: the numbers are 5 and 10.

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3 years ago
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Harlamova29_29 [7]
I'm going to say A and B
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Answer:

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