Question

Find the slope of the line that passes through (2, 1) and (6,2).

Answer 1

Answer:

$\boxed {\boxed {\sf m=\frac{1}{4}}}$

Step-by-step explanation:

The slope of a line can be found using the slope formula or dividing the change in y by the change in x.  

$m=\frac{y_2-y_1}{x_2-x_1}$

where (x₁, y₁) and (x₂, y₂) are the points the line passes through.

We are given the points (2,1) and (6,2). Therefore:

$x_1=2 \\y_1= 1\\x_2= 6\\y_2=2$

Substitute the points into the formula.

$m=\frac{2-1}{6-2}$

Solve the numerator.

• 2-1=1

$m=\frac{1}{6-2}$

Solve the denominator

• 6-2=4

$m=\frac{1}{4}$

This fraction cannot be reduced further, so it is the slope. It can be written as a decimal too:

$m= 0.25$

The slope of the line is 1/4 (0.25)

Answer 2

Answer:

$\boxed{m = \frac{1}{4}}$

.

Step-by-step explanation:

Use the form below

$\boxed{\boxed{m = \frac{y_2 - y_1}{x_2 - x_1} }}$

Where

• $m$ is a slope
• $(x_1,~y_1)$ and $(x_2,~y_2)$ are the point of the line

.

So, the slope is

$(2,~ 1) \to x_1 = 2~and~y_1 = 1$

$(6,~ 2) \to x_2 = 6~and~y_2 = 2$

.

$m = \frac{2-1}{6-2}$

$m = \frac{1}{4}$

.

Happy to help:)