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3 years ago

BRAINLIEST

Mathematics

1 answer:

Paraphin [41]3 years ago

8 0

You forgot to put a picture

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The combination for a lock is a 3-digit number. The digits are the prime factors of 42 listed from least to greatest. What is th

Dvinal [7]

Answer:

2, 3, 7

Step-by-step explanation:

Since you know your multiplication tables, you know that ...

42 = 6 × 7

and

6 = 2 × 3

The numbers 2, 3, and 7 are prime numbers (not further divisible). This list is in order least to greatest, so is the combination of the lock.

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3 years ago

not sure if this makes sense to you guys but if you can help that'd be great. 15 points(all i have left) due today. thank you!!

MAXImum [283]

Answer:

The graph that have 2 lines is for Question 21 and the graph with three lines is for Question 22

Step-by-step explanation:

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2 years ago

What is the value of g?

Lina20 [59]

Answer: G is 31 degrees

Step-by-step explanation: that angle is a right angle which means it measures 90 degrees. if we subtract the given measurement from 90 we get 31

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2 years ago

Read 2 more answers

5ft<br> 7ft<br> Area =<br> square ft<br> What is the answer please

maria [59]

i think the answer is 35 but i am not 100% sure

6 0

3 years ago

The J.O. Supplies Company buys calculators from a non-US supplier. The probability of a defective calculator is 10 percent. If 3

RSB [31]

Answer:

There is a 24.3% probability that one of the calculators will be defective.

Step-by-step explanation:

For each calculator, there are only two possible outcomes. Either it is defective, or it is not. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

The probability of a defective calculator is 10 percent.

This means that $p = 0.1$

If 3 calculators are selected at random, what is the probability that one of the calculators will be defective

This is P(X = 1) when n = 3. So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 1) = C_{3,1}.(0.1)^{3}.(0.9)^{2} = 0.243$

There is a 24.3% probability that one of the calculators will be defective.

3 0

3 years ago