A. Consider the cube shown below. Identify the two-dimensional shape of the cross-section if the cube is sliced horizontally.

I NEED HELP................................................... BRAINLIEST?

Mumz [18]

Remark

Good thing to know. This is a rounding question.

A

Answer A is a bit nasty. I round 5 to the next highest number on the left. That may not be what you have been told to do. Let us round A to 5.7 and see if anything else does this.

B

Answer B rounds to 5.6

C

Answer C rounds to 5.6 as well. 3 is less than 5 so you round down.

D

Answer D rounds to 5.6(.) The zero has no effect on the 6.

Answer

Since there is nothing special about A and nothing else rounds to 5.7, the answer is A. So your rule is when the last number is 5, you round the second last number to one more than it was, regardless of the properties of the second last number.

3 0

3 years ago

Mold grows on bread and every day it doubles by the eighth day the entire bread is covered with mold when was half the bread cov

Brut [27]

Answer:

The mold will cover half the area as much are one day before it.

Step-by-step explanation:

Given:

Every day the mold on bread grows doubles

And by 8th day entire bread covered with it.

To Find:

When was half the bread covered by mold.

Solution:

It is said that area covered by mold doubles on each day

Total days taken to cover entire bread are 8

Let Area of bread be A

So Area covered (A) corresponds to 8 days with doubling.

So on previous day it should What ever area on 8th day/2

i.e A(8)/2

Similar on 6th day A(7)/2

So on 5ht day =A(6)/2 ,4th= A(5)/2, on 3rd= A(4)/2, on 2nd=A(3)/2

On 1st =A(2)/2

So we required Area= half of total.

One day before the 8th day will be 7th day

on that day it will cover half are so that on next day will cover the double of the previous area consumed.

4 0

3 years ago

Find the domain and range of the function y = f(x)= √x-2 <img src="https://tex.z-dn.net/?f=%20%5Csqrt%7Bx%20-%202%7D%20" i

Over [174]

Answer:

3x-x+2=4

Step-by-step explanation:

The domain of f(x)=2^x would be the x values. This would include all values that you can input as x in order to make this problem work. The domain of a function is usually all real numbers. The range of f(x)=2^x would be the y values. This would include all values that would be the output for the y value. An example of this would be if you used 2 as x then the function would read f(x)=2^2. The y would equal 4 which would be included in the range of this function. To find the domain and range of the inverse you would follow the proper steps to get the inverse of the function which would be x=2^y. The domain would be the x values and the range would be the y values. If you put 4 as x which would be your input for the domain you would get 2^4 = 16 for the y which would be the range.

4 0

3 years ago

20. Sofia paid $11.80 for a pen, a marker, and a binder. The marker cost $0.80 more than the pen. The binder cost 4 times as muc

7nadin3 [17]

Answer:

$1.30

Step-by-step explanation:

Let x = the cost of the pencil

Let x + .80 = the cost of the pen

Let 4(x + .80) = the cost of the binder

x + x + .80 + 4(x + .80) = 11.80

2x + .80 + 4x + 3.20 = 11.80

6x + 4.00 = 11.80

6x = 7.80

x = $1.30

x + .80 = $2.10

4(x + .80) = $8.40

7 0

2 years ago

Read 2 more answers

How do I write an equation for each parabolas?

fredd [130]

Step-by-step explanation:

In the first parabola it opens on the left and the equation of parabola can be expressed as,

in vertical component (y)² = (-) a (x-h)² + k

cause the parabola is horizontal and it opens on the left.

2. In the second parabola the vertex opens on the right and hence the equation cane be given as,

in vertical component (y)² = a (x-h)² + k

cause the parabola is horizontal and opens on the right.

3. the third equation is given as,

in horizontal component (x²) = (-) a (x-h)² + k

since the parabola is vertical and opens down.

4. the fourth equation is given as,

in the horizontal component (x)² = a (x-h)² + k

since the parabola is vertical and opens up.

7 0

3 years ago