Can someone answer these two problems??
1 answer:
9514 1404 393
Answer:
B
Step-by-step explanation:
The given equation is in slope-intercept form:
y = mx + b
where the slope is m = -3 and the y-intercept is b = +2.
So, the graph will have a slope of ...
"rise"/"run" = -3 = -3/1
and will cross the y-axis at y=2.
Graphs A and B cross the y-axis in the right place, but only Graph B has a negative "rise" a x increases.
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Answer: The correct congruence statement is .
Explanation:
It is given that A triangle Q D J. The base D J is horizontal and side Q D is vertical. Another triangle M C W is made. The base C W and side M C are neither horizontal nor vertical. Triangle M C W is to the right of triangle Q D J.
The sides Q D and M C are labeled with a single tick mark. The sides D J and C W are labeled with a double tick mark. The sides Q J and M W are labeled with a triple tick mark.
Draw two triangles according to the given information.
From the figure it is noticed that
So by SSS rule of congruence we can say that .
