Answer:
A
Step-by-step explanation:
So we want to convert 59°F to Celsius using the given formula:
Thus, substitute F for 59:
Subtract:
Simplify:
The answer is A
I don’t know it can someone help me
1 answer:
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Let's first start off with an equation to represent Celeste's budget:
Where:
'h' is the money in dollars that she needs to get her hair cut
'p' is the money in dollars that she needs to get her hair permed
'l' is the money in dollars that she needs for lunch
Now let's simplify this equation using the information that was given:
*This must be true since it is told that she needs $5 for lunch
*This is because the perm costs twice as much as the hair cut
Our new/updated equation is:
This is much easier to solve, let's rearrange and solve for 'p':
Therefore the perm costs $36
I hope this helps! Let me know if you have any further questions.
Where:
'h' is the money in dollars that she needs to get her hair cut
'p' is the money in dollars that she needs to get her hair permed
'l' is the money in dollars that she needs for lunch
Now let's simplify this equation using the information that was given:
Our new/updated equation is:
This is much easier to solve, let's rearrange and solve for 'p':
Therefore the perm costs $36
I hope this helps! Let me know if you have any further questions.
Answer:
2x +12y = -63 . . . in standard form
y = -1/6x -21/4 . . . in slope-intercept form
Step-by-step explanation:
It is useful to find the midpoint of the segment. That is the average of the end points:
M = ((-1, -2) +(-2, -8))/2 = ((-1-2)/2, (-2-8)/2) = (-3/2, -5)
It is also useful to find the changes in coordinates from B to A:
Δ = A-B = (-1-(-2), -2-(-8)) = (1, 6)
From here, there are a couple of ways you can write the equation of the perpendicular line.
__
One way is to use the Δ values to compute the slope of the segment. The perpendicular line will have a slope that is the negative reciprocal of that.
Δy/Δx = 6/1 = 6
m = -1/6 . . . . . slope of the perpendicular line
Now we have a point and a slope for the desired line, so we can use a point-slope form of the equation for a line:
y = m(x -h) +k
y = (-1/6)(x -(-3/2)) +(-5)
y = (-1/6)x -21/4 . . . . . . . . eliminate parentheses; point-slope form
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Another way to write the perpendicular line is to use the Δ values directly as coefficients in the standard form equation:
Δx(x -h) +Δy(y -k) = 0
1(x -(-3/2)) + 6(y -(-5)) = 0 . . . substitute values
x +6y +31.5 = 0 . . . . . . . . . . .collect terms
2x +12y = -63 . . . . . . . . . . . . multiply by 2, put in standard form
