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Alex17521 [72]
3 years ago
15

TIMEDD EASY PLS HELP NO LINKS

Mathematics
1 answer:
melamori03 [73]3 years ago
7 0
1/3 πr^2h
1/3 π2
2/3 π
answer : A
good luck
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Simplify the expression <br> 9y+4-6y
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Answer:

3y+4

Step-by-step explanation:

9y-6y=3y

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Adrian has 75 coins consisting of quarters and dimes. The combined value of the coins is $10.20. How many of each type of coin d
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40 quarters and 2 dimes

Step-by-step explanation:

I did .25 (the amount of a quarter) and put it into a calculator adding.25 untill I got to 10 and then just 2 dimes bc 10+10 is 20

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2 years ago
PLZ HURRY Solve for g.<br><br>g3 – 1 &gt; 2
Phoenix [80]

g3 - 1 > 2

g3 - 1 + 1 > 2 + 1

g3 > 3

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//

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5 0
3 years ago
(-3.2) to the power of 0
stellarik [79]

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Step-by-step explanation:

5 0
3 years ago
According to the National Association of Colleges and Employers, the average starting salary for new college graduates in health
katen-ka-za [31]

Answer:

a) The probability that a new college graduate in business will earn a starting salary of at least $65,000 is P=0.22965 or 23%.

b) The probability that a new college graduate in health sciences will earn a starting salary of at least $65,000 is P=0.11123 or 11%.

c) The probability that a new college graduate in health sciences will earn a starting salary of less than $40,000 is P=0.14686 or 15%.

d) A new college graduate in business have to earn at least $77,133 in order to have a starting salary higher than 99% of all starting salaries of new college graduates in the health sciences.

Step-by-step explanation:

<em>a. What is the probability that a new college graduate in business will earn a starting salary of at least $65,000?</em>

For college graduates in business, the salary distributes normally with mean salary of $53,901 and standard deviation of $15,000.

To calculate the probability of earning at least $65,000, we can calculate the z-value:

z=\frac{x-\mu}{\sigma} =\frac{65000-53901}{15000} =0.74

The probability is then

P(X>65,000)=P(z>0.74)=0.22965

The probability that a new college graduate in business will earn a starting salary of at least $65,000 is P=0.22965 or 23%.

<em>b. What is the probability that a new college graduate in health sciences will earn a starting salary of at least $65,000?</em>

<em />

For college graduates in health sciences, the salary distributes normally with mean salary of $51,541 and standard deviation of $11,000.

To calculate the probability of earning at least $65,000, we can calculate the z-value:

z=\frac{x-\mu}{\sigma} =\frac{65000-51541}{11000} =1.22

The probability is then

P(X>65,000)=P(z>1.22)=0.11123

The probability that a new college graduate in health sciences will earn a starting salary of at least $65,000 is P=0.11123 or 11%.

<em>c. What is the probability that a new college graduate in health sciences will earn a starting salary less than $40,000?</em>

To calculate the probability of earning less than $40,000, we can calculate the z-value:

z=\frac{x-\mu}{\sigma} =\frac{40000-51541}{11000} =-1.05

The probability is then

P(X

The probability that a new college graduate in health sciences will earn a starting salary of less than $40,000 is P=0.14686 or 15%.

<em />

<em>d. How much would a new college graduate in business have to earn in order to have a starting salary higher than 99% of all starting salaries of new college graduates in the health sciences?</em>

The z-value for the 1% higher salaries (P>0.99) is z=2.3265.

The cut-off salary for this z-value can be calculated as:

X=\mu+z*\sigma=51,541+2.3265*11,000=51,541+25,592=77,133

A new college graduate in business have to earn at least $77,133 in order to have a starting salary higher than 99% of all starting salaries of new college graduates in the health sciences.

8 0
3 years ago
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