Doug says that this clock shows 8:43.is he correct? Explain why or why not.

Mathematics

2 answers:

ss7ja [257]3 years ago

5 0

Is this a joke because it made me laugh

katen-ka-za [31]3 years ago

5 0

It looks more like 8:42. The small hand would have to be one more tick closer to the 9 to be at 8:43.

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How do I solve this

Kitty [74]

Hello,

$x^2-2x-27=-5x+1\\

x^2-2x+5x-27-1=0\\

x^2+3x-28=0\\

x^2+7x-4x-28=0\\

x(x+7)-4(x+7)=0\\

(x+7)(x-4)=0\\

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4 years ago

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Which domain restrictions apply to the rational expression?

andre [41]

Both expression have the same denominator: 9x²-1. Thus it must not be 0.

9x²-1=(3x-1)(3x+1)=0, resulting x=+-1/3.

Restrictions: x in R\{-1/3, 1/3}

Adding those expressions:

E=(-x-2)/(9x²-1 ) + (-5x+4)/(9x²-1)=

(-x-2-5x+4)/(9x²-1)=(-6x+2)/(9x²-1)=

(-2)(3x-1)/(9x²-1)=-2/(3x+1)

E=-2/(3x+1)

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3 years ago

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Ksivusya [100]

1. $m\angle BAC=m\angle CAD,\ m\angle ACB=m\angle ADC=90^{\circ}$ , then $m\angle ABC=m\angle ACD$ and triangles ADC and ACB are similar by AAA theorem.

2. The ratio of the corresponding sides of similar triangles is constant, so

$\dfrac{AC}{AB}= \dfrac{AD}{AC}$ .

3. Knowing lengths you could state that $\dfrac{b}{c}= \dfrac{e}{b}$ .

4. This ratio is equivalent to $b^2=ce$ .

5. $m\angle ABC=m\angle CBD,\ m\angle ACB=m\angle CDB=90^{\circ}$ , then $m\angle BAC=m\angle BCD$ and triangles BDC and BCA are similar by AAA theorem.