Direction vector of line of intersection of two planes is the cross product of the normal vectors of the planes, namely
p1: x+y+z=2
p2: x+7y+7z=2
and the corresponding normal vectors are: (equiv. to coeff. of the plane)
n1:<1,1,1>
n2:<1,7,7>
The cross product n1 x n2
vl=
i j l
1 1 1
1 7 7
=<7-7, 1-7, 7-1>
=<0,-6,6>
Simplify by reducing length by a factor of 6
vl=<0,-1,1>
By observing the equations of the two planes, we see that (2,0,0) is a point on the intersection, because this points satisfies both plane equations.
Thus the parametric equation of the line is
L: (2,0,0)+t(0,-1,1)
or
L: x=2, y=-t, z=t
option c is the answer....
Answer:
<u>30 pesos</u>
Step-by-step explanation:
<u>Given</u>
- Had 200 pesos originally
- spends 'y' pesos on a notebook
- Bought 4 colored pens with the rest of the money
<u>Solving</u>
- Let money of the pen = x, money of notebook = y
- 4x + y = 200
- 4x + 80 = 200
- 4x = 120
- x = <u>30 pesos</u>
Answer:
Trial- 2 shows the conservation of momentum in a closed system.
Step-by-step explanation:
Given: Mass of balls are 
Conservation of momentum in a closed system occurs when momentum before collision is equal to momentum after collision.
- Let initial velocity of ball
- Initial velocity of ball
- Final velocity of ball
- Final velocity of ball
- Momentum before collision
- Momentum after collision
Now, According to conservation of momentum.
Momentum before collision = Momentum after collision
We will plug each trial to this equation.
Trial 1
Trial 2
Trial 3
Trial 4
We can see only Trial 2 satisfies the princple of conservation of momentum. That is momentum before collison should equal to momentum after collision.
This is the last one right?
