Ask question

Ask question

All categories

3 years ago

8

Is this correct.... I not really good at math... plz help me

2 answers:

saul85 [17]3 years ago

6 0

Answer:

<h2>no</h2>

Step-by-step explanation:

In order to figure out the problem try to make the twenty into ten. also remember that 20% is 2/10 or 1/5. so if you want to do it with ten pieces how many color in two, or with 20 what’s one fifth of 20? It’s 4. So you need to shade in 4 pieces.

adell [148]3 years ago

4 0

Pretty sure it’s correct sir

You might be interested in

Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.

liubo4ka [24]

Answer:

P Q R S T _4.5

Step-by-step explanation:

uuuuuuuuuuuuuuuuuuukkkkkkkkkkkkkkkkkkggggggggggggggggggttttttt

6 0

3 years ago

Find the reduced row echelon form of the following matrices and then give the solution to the system that is represented by the

GaryK [48]

Answer:

a)

Reduced Row Echelon:

$\left[\begin{array}{cccc}1&1/2&0&0\\0&1&7/4&0\\0&0&1&-4\end{array}\right]$

Solution to the system:

$x_3=-4\\x_2=-\frac{7}{4}x_3=7\\x_1=-\frac{1}{2}x_2=-\frac{7}{2}$

b)

Reduced Row Echelon:

$\left[\begin{array}{cccc}4&3&0&7\\0&0&2&-17\\0&0&2&-17\end{array}\right]$

Solution to the system:

$x_3=-\frac{17}{2}\\x_1=\frac{7-3x_2}{4}$

x_2 is a free variable, meaning that it has infinite possibilities and therefore the system has infinite number of solutions.

Step-by-step explanation:

To find the reduced row echelon form of the matrices, let's use the Gaussian-Jordan elimination process, which consists of taking the matrix and performing a series of row operations. For notation, R_i will be the transformed column, and r_i the unchanged one.

a) $\left[\begin{array}{cccc}0&4&7&0\\2&1&0&0\\0&3&1&-4\end{array}\right]$

Step by step operations:

1. Reorder the rows, interchange Row 1 with Row 2, then apply the next operations on the new rows:

$R_1=\frac{1}{2}r_1\\R_2=\frac{1}{4}r_2$

Resulting matrix:

$\left[\begin{array}{cccc}1&1/2&0&0\\0&1&7/4&0\\0&3&1&-4\end{array}\right]$

2. Set the first row to 1

$R_3=-3r_2+r_3$

Resulting matrix:

$\left[\begin{array}{cccc}1&1/2&0&0\\0&1&7/4&0\\0&0&1&-4\end{array}\right]$

3. Write the system of equations:

$x_1+\frac{1}{2}x_2=0\\x_2+\frac{7}{4}x_3=0\\x_3=-4$

Now you have the reduced row echelon matrix and can solve the equations, bottom to top, x_1 is column 1, x_2 column 2 and x_3 column 3:

$x_3=-4\\x_2=-\frac{7}{4}x_3=7\\x_1=-\frac{1}{2}x_2=-\frac{7}{2}$

b)

$\left[\begin{array}{cccc}4&3&0&7\\8&6&2&-3\\4&3&2&-10\end{array}\right]$

1. $R_2=-2r_1+r_2\\R_3=-r_1+r_3$

Resulting matrix:

$\left[\begin{array}{cccc}4&3&0&7\\0&0&2&-17\\0&0&2&-17\end{array}\right]$

2. Write the system of equations:

$4x_1+3x_2=7\\2x_3=-17$

Now you have the reduced row echelon matrix and can solve the equations, bottom to top, x_1 is column 1, x_2 column 2 and x_3 column 3:

$x_3=-\frac{17}{2}\\x_1=\frac{7-3x_2}{4}$

x_2 is a free variable, meaning that it has infinite possibilities and therefore the system has infinite number of solutions.

7 0

3 years ago

Please help i give brainliest

Marina86 [1]

Answer:

all FALSE except 3 and 4

Step-by-step explanation:

Hope this helps

6 0

3 years ago

Read 2 more answers

Evaluate, M squared + mtp if m=3, t=4 and p=7

navik [9.2K]

m square +84 is the answer

3 0

4 years ago

Need answers to the ones that i haven’t written anything for

Trava [24]

Answer:

domain - (-infinity,infinity)

range - (-infinity, 2]

axis of sym - x=-1

y int - (0,-1)

at what value (row 1) - (-1,2)

Step-by-step explanation:

domain is side to side, it never ends bc of the arrows

range is top to bottom, there is no bottom bc of the arrow, but it has a top at 2 (the value on the y axis)

the axis of sym is basically the line that runs through the vertex, it's where you could fold it in half and it would still match up

8 0

3 years ago