During a 60-minute television program 25% of the time is used for the opening and closing credits. How many minutes remain for t
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Hi!
This question is about math.
<u><em>Least Common Factor 4 or 8: 8</em></u>
<u><em>Factors of 4 : 1, 2, 4 (prime factorization) (2*2)</em></u>
<u><em>Factors of 8: 1, 2, 4, 8 (prime factorization) (2*2*2)</em></u>
<u><em>Least Common Factor of a,b is the smallest positive number that divisible by both a and b.</em></u>
<em>Multiply each factor the greatest number of times it occurs in either 4 or 8.</em>
<em>Then multiply by the numbers.</em>
<em>Multiply each numerator by the same amount needed to multiply its corresponding denominator to turn it into the Least Common Factor of 8.</em>
<em>For 1/4 multiply the denominator and numerator by the 2.</em>
<em>Since the denominator are equal, combine the fractions.</em>
<em>Add the numbers 2+5=7</em>
Hope this helps! Thank you for posting your question at here on Brainly. Have a great day.
-Charlie
Answer:
The p-value of the test is 0 < 0.05, which means that there is significant evidence to conclude that more people utilize the bike lane after the change.
Step-by-step explanation:
Before the upgrade, on any given day, it was known that the section of road saw an average of 350 unique cyclists. Test if more people are using now.
At the null hypothesis, we test if the same number of people is still using, that is, the mean is 350. So
At the alternate hypothesis, we test if this mean increased, that is:
The test statistic is:
In which X is the sample mean, is the value tested at the null hypothesis, s is the standard deviation of the sample and n is the size of the sample.
350 is tested at the null hypothesis:
This means that
After the upgrade, they took a random sample of 35 days in the year and counted the number of unique cyclists each day. The average was 405 cyclists with a standard deviation of 25.
This means that .
Test statistic:
P-value of the test and decision:
The p-value of the test is the probability of finding a sample mean above 405, which is a right-tailed test with t = 13.02 and 35 - 1 = 34 degrees of freedom.
Using a t-distribution calculator, this probability is of 0.
The p-value of the test is 0 < 0.05, which means that there is significant evidence to conclude that more people utilize the bike lane after the change.