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Alex787 [66]
3 years ago
8

During a 60-minute television program 25% of the time is used for the opening and closing credits. How many minutes remain for t

he program itself
Mathematics
2 answers:
Gemiola [76]3 years ago
8 0

Answer:

The time used for the show itself is 45 minutes.

Step-by-step explanation:

25% of 60 minutes were used for the credits. We can see how long the credits last by dividing 60 by 4.

60 ÷ 4 = 15

We know that 15 minutes were used for the credits. That leaves 45 minutes

(60 - 15 = 45) for the program itself!

Vinil7 [7]3 years ago
3 0

Answer:

25%

Step-by-step explanation:

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Step-by-step explanation:

1,239 + 8,568= 9,807 ≈ 10000

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Find the area round to two decimal places as needed
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To find the area of an obtuse triangle you have to multiply the base of the triangle by the vertical height and divide the result by 2 following the formula:

A=\frac{b\cdot h}{2}

The base of the triangle is b= 7 miles and the height is h= 8 miles, using these lengths calculate the area as follows:

\begin{gathered} A=\frac{7\cdot8}{2} \\ A=\frac{56}{2} \\ A=28mi^2 \end{gathered}

The area of the triangle is 28 square miles.

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1 year ago
If x represents a number, write an expression to represent a number which is 5 less than 3 times x
Nitella [24]

Answer:

the correct answer is x = 3x - 5

6 0
3 years ago
1 2/3 X 3/4 what is the awnser with work shown
alex41 [277]
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6 0
3 years ago
In the diagram, TC represents a vertical building. The points, A and B, are on the same level as the foot C of the building such
Alenkinab [10]

Answer:

(a) The height of the building is 60.06 m

(b) The distance AB is 139.43 m

Step-by-step explanation:

The given parameters are

Given that segment BT = segment AT + 29

By trigonometric ratios, we have;

cos∠ATC = CT/AT

cos∠BTC = CT/BT

Therefore, we have;

cos(40°) = CT/AT.................................(1)

cos(56°) = CT/BT = CT/(AT + 29).....(2)

cos(56°) = CT/(AT + 29)......................(3)

From equation (1)

CT = AT×cos(40°)

From equation (3)

AT×cos(56°) + 29 × cos(56°) = CT

Therefore;

AT×cos(40°) = AT×cos(56°) + 29 × cos(56°)

AT×cos(40°) - AT×cos(56°) =  29 × cos(56°)

AT×(cos(40°) - cos(56°)) =  29 × cos(56°)

AT = 29 × cos(56°)/(cos(40°) - cos(56°)) = 78.4 m

TC = CT = AT×cos(40°) = 78.4×cos(40°) = 60.06 m

The height of the building = 60.06 m

(b) BT = AT + 29 = 78.4 m + 29 m= 107.4 m

AB = AT×sin(∠ATC ) + BT×sin(∠BTC) = 78.4×sin(40°) + 107.4×sin(56°) =  139.43 m

The distance AB =  139.43 m.

6 0
3 years ago
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