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3 years ago

Which of the following numbers is not part of the solution x ≤ -2

Mathematics

2 answers:

Ainat [17]3 years ago

8 0

Answer:

Step-by-step explanation:

In order for it to be the solution, it must be less than or equal to -2. D (-1.76) is bigger than -2, which means it is not a part of the solution.

Westkost [7]3 years ago

8 0

Answer:

Step-by-step explanation:

First of all, let's try all of the options available.

We know that x must be LESS THAN or EQUAL to -2

So, let's get on with it!

Option A:

Is -2.45 LESS THAN or EQUAL to -2?

Well, according to the number line, if the number is left of the number that you are comparing, -2 then it is less than.

So this option is alright.

Option B:

-2 is not LESS THAN but ONLY EQUAL to -2.

So this option I THINK is alright, but am not sure. But I think it is alright because if it is less than and equal to, then that means it ALSO INCLUDES -2.

Option C:

Again, -8 is located to the LEFT side of -2, which means -8 IS LESS THAN or Equal to -2.

So this option is alright.

Option D:

-1.76 is to the RIGHT side of -2, which means it is GREATER than -2.

So this option is CUT OFF

Hope this helps.

If you got it wrong , I am truly sorry... pls mark me brainliest if possible... I've never been marked that.

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If the squared difference of the zeroes of the quadratic polynomial x2+kx+30 is equal to 169 find the value of k and the zeroes

anyanavicka [17]

ANSWER

$x = 2 \: \: or \: \: x = 15$

$x = - 2 \: \: or \: \: x = - 15$

EXPLANATION

The given polynomial is

$f(x) = {x}^{2} + kx + 30$

where a=1,b=k, c=30

Let the zeroes of this polynomial be m and n.

Then the sum of roots is

$m + n = - \frac{b}{a} = -k$

and the product of roots is

$mn = \frac{c}{a} = 30$

The square difference of the zeroes is given by the expression.

$( {m - n})^{2} = {(m + n)}^{2} - 4mn$

From the question, this difference is 169.

This implies that:

$( { - k)}^{2} - 4(30) = 169$

${ k}^{2} -120= 169$

$k^{2} = 289$

$k= \pm \sqrt{289}$

$k= \pm17$

We substitute the values of k into the equation and solve for x.

$f(x) = {x}^{2} \pm17x + 30$

$f(x) = (x \pm2)(x \pm 15)$

The zeroes are given by;

$(x \pm2)(x \pm 15) = 0$

$x = \pm2 \: \: or \: \: x = \pm 15$

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<h2>Hello!</h2>

The answer is:

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