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zhannawk [14.2K]
3 years ago
15

Mhanifa please help :( no one has helped me on this yet

Mathematics
1 answer:
VMariaS [17]3 years ago
3 0

Answer:

16)

  • q / 12 = sin 20
  • q = 12 sin 20
  • q = 4.1
  • p / 12 = cos 20
  • p = 112 cos 20
  • p = 11.3

17)

  • x / 44 = tan 39
  • x = 44 tan 39
  • x = 35.6
  • 35.6 / y = sin 39
  • y = 35.5 / sin 39
  • y = 56.4

18)

  • 14 / b = sin 57
  • b = 14 / sin 57
  • b = 16.7
  • a / 16.7 = cos 57
  • a = 16.7 cos 57
  • a = 9.1
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On your tenth birthday, you received 500 which you invested at 9.5% interest, compounded annually. your investment is worth $250
igomit [66]
Compounded once a year: A=P(1+r)^t
2500=500(1+0.095)^t
1.095^t=5
because the unknown number is an exponent, use log to find the unknown:
log(1.095^t)=log5
tlog1.095=log5
t=log5/log1.095
use your calculator, t=17.734
so this person is about 28 years old.
6 0
3 years ago
Someone smart help me please
mafiozo [28]
Pretty sure it is
shift 1 left
i might be wrong
7 0
3 years ago
Factor completely 2x^2+4x-70
Fittoniya [83]

Answer: 2(x-5)(x+7) <---- this is your answer

Step-by-step explanation:

(2x^2+4x-70)

2((x-5)(x+7))

(-1,-72)

(-1, -\frac{575}{8} )

x=-1

y=-\frac{577}{8}

Factor the polynomial completely.

Group and factor out the greatest common factor (GCF), then combine.

Graph the parabola using the direction, vertex, focus, and axis of symmetry.

Direction: Opens Up

So the answer is 2(x-5)(x+7)

Hope this helps out :)

4 0
2 years ago
Look at the picture attached :)
Karolina [17]
I think it is B
Not sure
4 0
3 years ago
Consider the probabilities of people taking pregnancy tests. Assume that the true probability of pregnancy for all people who ta
Valentin [98]

Using conditional probability, it is found that there is a 0.8462 = 84.62% probability that a woman who gets a positive test result is truly pregnant.

<h3>What is Conditional Probability?</h3>

Conditional probability is the probability of one event happening, considering a previous event. The formula is:

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

  • P(B|A) is the probability of event B happening, given that A happened.
  • P(A \cap B) is the probability of both A and B happening.
  • P(A) is the probability of A happening.

In this problem, the events are:

  • Event A: Positive test result.
  • Event B: Pregnant.

The probability of a positive test result is composed by:

  • 99% of 10%(truly pregnant).
  • 2% of 90%(not pregnant).

Hence:

P(A) = 0.99(0.1) + 0.02(0.9) = 0.117

The probability of both a positive test result and pregnancy is:

P(A \cap B) = 0.99(0.1)

Hence, the conditional probability is:

P(B|A) = \frac{0.99(0.1)}{0.117} = 0.8462

0.8462 = 84.62% probability that a woman who gets a positive test result is truly pregnant.

You can learn more about conditional probability at brainly.com/question/14398287

7 0
2 years ago
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