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balandron [24]
3 years ago
6

PLEASE HELP IN THE ATTACHED IMAGE

Mathematics
1 answer:
Serga [27]3 years ago
4 0

Answer:

864x^2 + 102x + 24559

Step-by-step explanation:

Add the correct terms that correspond to the placement.

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What is the solution to the system of equations?<br> y=2/3x+3 x=-2
nydimaria [60]

Answer:

The solution to the system of equations is (1.6,-2)

Step-by-step explanation:

You have to plug the x which is -2 into the equation.

You would get y=2/3(-2)+3

Then you would calculate that to get y=1.6

Lastly you combine the y answer to the x answer to get the coordinates (1.6,-2)

3 0
3 years ago
Help please ...................
GarryVolchara [31]

Answer:

2( \frac{1}{2}5 \times 6.4)  + 2( \frac{1}{2} 5 \times 12.4) \\  = 2(16) + 2(31) \\  = 32 + 62 \\  = 94m ^{2}

6 0
3 years ago
Read 2 more answers
Solve using elimination.<br> 5x - 6y = 2<br> -5x - 5y = 20
s344n2d4d5 [400]

Answer:

x = -2, y =-2

Step-by-step explanation:

5x - 6y = 2

-5x - 5y = 20

Add the two equations together to eliminate x

5x - 6y = 2

-5x - 5y = 20

------------------------

-11y = 22

Divide by -11

-11y/-11 = 22/-11

y = -2

Now we can find x

5x -6(-2) =2

5x +12 = 2

Subtract 12 from each side

5x +12-12 =2-12

5x = -10

Divide by 5

5x/5 = -10/5

x = -2

6 0
3 years ago
A bus leaves a station traveling north at 70 kilometers per hour. Half an hour later a
Semenov [28]

Answer:

280 km

Step-by-step explanation:

Given that a bus, say b_1, leaves a station traveling north at speed of  70km/hour.

Half an hour later the second bus, say b_2,  leaves a station traveling north at speed of  70km/hour.

As, distance = speed x time,

so, the distance traveled by bus b_1 in 0.5 hours = 70 x 0.5 = 35 km.

Note that, both the buses are traveling in the same direction and when the second bus leaves the station, the first bus already covered a distance of 35 km.

Let the second bus took t hours to meet the first bus and both the buses meet at a distance of d km from the station.

The distance traveled by the first bus from the station, d = 35 + 70t km

\Rightarroe t= \frac {d-35}{70}\cdots(i)

and the distance traveled by the second bus, d = 80t km

\Rightarrow t=\frac {d}{80}\cdots(ii)

Now, equation the equation (i) and (ii), we have

\frac {d-35}{70}=\frac {d}{80} \\\\\Rightarrow 8(d-35)=7d \\\\\Rightarrow 8d - 280 = 7d \\\\\Rightarrow 8d-7d=280 \\\\\Rightarrow d = 280 km

Hence, both the bus will meet at a distance of 280 km from the station.

7 0
2 years ago
Select the equation represented by the graph ​
valentinak56 [21]

Answer:

b) y = -2/3 + 1

Step-by-step explanation:

The format for the equation is y = mx + b

(m is the slope, and b is the y intercept)

Slope is rise over run (the units the line moves up and the units the line moves to the right)

In this case, the slope is: -2/3 because it goes down 2 and to the right 3.

The y intercept is 1.

This makes our equation:

y = -2/3 + 1

4 0
3 years ago
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