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Vera_Pavlovna [14]

2 years ago

14

How much would each starburst weigh if 3 starburst weigh 1 ounce?

1 answer:

sineoko [7]2 years ago

6 0

Answer:

3 ounces

Step-by-step explanation:

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Which expression is equivalent to the following complex fraction?

jeka57 [31]

$\dfrac{\frac{1}{x}-\frac{1}{y}}{\frac{1}{x}+\frac{1}{y}}=\dfrac{\frac{y}{xy}-\frac{x}{xy}}{\frac{y}{xy}+\frac{x}{xy}}=\dfrac{\frac{y-x}{xy}}{\frac{y+x}{xy}}=\dfrac{(y-x)xy}{(y+x)xy}=\dfrac{y-x}{y+x}$

Answer D.

6 0

3 years ago

Two circles of radius 8 are tangent to the graph of

KengaRu [80]

Two circles<span> of </span>radius<span> 4 are </span>tangent<span> to the </span>graph<span> of y^</span>2<span> = </span>4x<span> at the </span>point<span> (</span>1<span>, </span>2<span>). ... I know how to </span>find<span> the </span>tangent<span> line from a circle and a given </span>point<span>, but ... </span>2a2=42. a2=8. a=±2√2. Then1−xc=±2√2<span> and </span>2−yc=±2√2. ... 4 from (1,2<span>), so you could </span>find these<span> centers, and from there the</span>equations<span> of the circle

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5 0

3 years ago

HALP URGENT PLS im dum <br><br><br>x =x=x, equals <br><br>^\circ <br><br>∘

deff fn [24]

Considering the angle of the ray, it is found that the value of x is of x = 55º.

<h3>What is the angle of the ray?</h3>

The ray has an angle of 180º. It is composed by:

Angle x.

An angle of 35º.

An angle of 90º.

Hence:

x + 35 + 90 = 180

x = 180 - 125

x = 55º.

More can be learned about angles and rays at brainly.com/question/25770607

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7 0

2 years ago

Read 2 more answers

Kendrick adds 1/2cup of chicken stock to a pot. Then he takes 1/2 cup of stock out of the pot. What is the overall increase or d

Hoochie [10]

Answer:

there isnt any increase or decrease

8 0

3 years ago

1.) What is the equation of the path of firework #1? Write your equation in general form.

valina [46]

1. I'm assumig that the paths are perfect parabolas

this means that their general forms can be written in $y=ax^2+bx+c$

it's easier to find vertex form first then expand to get general form

vertex form is $y=a(x-h)^2+k$ where the vertex is (h,k) and a is a constant

firework #1

vertex is (10,50), so (h,k)=(10,50) and h=10, k=50

$h_1=a(t-10)^2+50$

to find the value of $a$ , subsitute another point

(0,0)

$0=a(0-10)^2+50)$

$0=100a+50$

$a=\frac{-1}{2}$

so the equation in vertex form is $h_1=\frac{-1}{2}(t-10)^2+50$

expand to get general form

$h_1=\frac{-1}{2}(t^2-20t+100)+50$

$h_1=\frac{-1}{2}t^2+10t-50+50$

$h_1=\frac{-1}{2}t^2+10t$

2.

same as last time

vertex is (10,72) so (h,k)=(10,72) so h=10 and k=72

equation is $h_2=a(t-10)^2+72$

find $a$

use another point

(0,22)

$22=a(0-10)^2+72$

$22=100a+72$

$-50=100a$

$a=\frac{-1}{2}$

so the equation in vertex form is $h_2=\frac{-1}{2}(t-10)^2+72$

3.

range is the numbers that h is allowed to be

think about what h represents. it represents the height of the rocket

from the graph, we can see that the lowest possible height is 0yd and the highest height is 50yd

so range is 0 to 50 or 0≤h≤50

domain is the numbers that t is allowed to be

think about what t represents. it represents how long the rocket has been flying

it will stop flying when it hits the ground or at t=20

it starts flying at t=0

so domain is from 0 to 20 or 0≤t≤20

3 0

3 years ago