Question

For this problem, involving a weighted die, assume that the outcomes 1 through 4 are equally likely, that the outcomes 5 through 6 are equally likely, and that outcome 1 is 3 times as likely as outcome 5.
(1) What probability should be assigned to rolling a 4?


(2) What probability should be assigned to rolling a 6?

Answer 1

Answer:

a.$\frac{3}{14}$

b.$\frac{1}{14}$

Step-by-step explanation:

We are given that a die is rolled

Let x bet the cases in favor of 5.

Number of cases in favor of 6=x

Then according to question

Number of cases in favor of  1=3x

Number of cases in favor of 2=3x

Number of cases in favor of 3=3x

Number of cases in favor of 4=3x

Sum of total cases=$x+x+3x+3x+3x+3x=14x$

Probability of getting 5 =$\frac{x}{14x}=\frac{1}{14}$

Probability of getting 1=$\frac{3x}{14x}=\frac{3}{14}$

1.We have to find probability should be assigned to rolling a 4.

The probability of getting =$\frac{3}{14}$

2.We have to find the probability of rolling 6.

The probability of getting 6=$\frac{1}{14}$