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nignag [31]
2 years ago
7

PLEASE HELP!!!

Mathematics
1 answer:
Brums [2.3K]2 years ago
6 0

Answer:

  • 2.21 gallons

Step-by-step explanation:

<u>Area of sides:</u>

  • 2(10*3 + 1/2(14 + 10)*6) = 204 square feet

<u>Area of the bottom:</u>

  • 20(3 + 10 + 5 + 10 + 6) = 680 square feet

<u>Total area:</u>

  • 204 + 680 = 884 square feet

<u>Paint needed:</u>

  • 884 / 400 = 2.21 gallons
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lesya [120]

Answer:

13

Step-by-step explanation:

We can use the slope formula to find the slope

m = ( y2-y1)/(x2-x1)

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The length of a rectangle is increasing at a rate of 6 cm/s and its width is increasing at a rate of 5 cm/s. When
atroni [7]

Answer:

The area of the rectangle is increasing at a rate of 84 square centimeters per second.

Step-by-step explanation:

The area for a rectangle is given by the formula:

A=w\ell

Where <em>w</em> is the width and <em>l</em> is the length.

We are given that the length of the rectangle is increasing at a rate of 6 cm/s and that the width is increasing at a rate of 5 cm/s. In other words, dl/dt = 6 and dw/dt = 5.

First, differentiate the equation with respect to <em>t</em>, where <em>w</em> and <em>l</em> are both functions of <em>t: </em>

\displaystyle \frac{dA}{dt}=\frac{d}{dt}\left[w\ell]

By the Product Rule:

\displaystyle \frac{dA}{dt}=\frac{dw}{dt}\ell +\frac{d\ell}{dt}w

Since we know that dl/dt = 6 and that dw/dt = 5:

\displaystyle \frac{dA}{dt}=5\ell + 6w

We want to find the rate at which the area is increasing when the length is 12 cm and the width is 4 cm. Substitute:

\displaystyle \frac{dA}{dt}=5(12)+6(4)=84\text{ cm}^2\text{/s}

The area of the rectangle is increasing at a rate of 84 square centimeters per second.

8 0
3 years ago
Help plz 20 pts TOTAL 10 pts each
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Answer:

This question needs a step to step long explanation.

5 0
3 years ago
The Pythagorean theorem is a² + b² = c². Solve for b. b=±c+a−−−−√ b=±c2−a2−−−−−−√ b=±c2+a2−−−−−−√ b=±c−a−−−−√
uysha [10]

a^{2} +b^{2} =c^{2}

As we have to solve for b, it means we have to isolate b

So first of all subtract a^{2} from both sides

So we get

b^{2} =c^{2} -a^{2}

Now we need b , but its b^2 , so we can take square root on both sides.


taking square roots on both sides

b= +- \sqrt{c^2 -a^2}


Hence option B is correct

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