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Mnenie [13.5K]
4 years ago
5

Can someone help me with this problem?

(18x^2+9x-7)/3x" alt="(18x^2+9x-7)/3x" align="absmiddle" class="latex-formula">

Mathematics
1 answer:
Fantom [35]4 years ago
5 0
I hope this helps you

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In a sample of 600 college students, 87.2% said they graduated from high school. How many of the students graduated from high sc
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523.2 students

Step-by-step explanation:

87.2%×600=523.2 students

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Square perimeter= 20 triangle base= 3 and height =3.5 find the percentage of the area inside the square shaded
Lisa [10]

Answer:

Area of geometric figures mentioned calculated.

Step-by-step explanation:

Square Perimeter = 4 x sides of square = 20. So, each equal side of square = 20 / 4 = 5

Area of square = ( Side )^2 = ( 5 )^2 = 25

Area of triangle = 1/2 (Base) (Height) = 1/2 x 3 x 3.5 = 5.25

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3 years ago
How many place values follow the decimal point in the problem below?<br> 2.01 x 4.1
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Step-by-step explanation:

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Sin2x-sin2xcos2x=sin4x
yaroslaw [1]

It looks like the given equation is

sin(2x) - sin(2x) cos(2x) = sin(4x)

Recall the double angle identity for sine:

sin(2x) = 2 sin(x) cos(x)

which lets us rewrite the equation as

sin(2x) - sin(2x) cos(2x) = 2 sin(2x) cos(2x)

Move everything over to one side and factorize:

sin(2x) - sin(2x) cos(2x) - 2 sin(2x) cos(2x) = 0

sin(2x) - 3 sin(2x) cos(2x) = 0

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Then we have two families of solutions,

sin(2x) = 0   or   1 - 3 cos(2x) = 0

sin(2x) = 0   or   cos(2x) = 1/3

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… … …   or   [2x = arccos(1/3) + 2nπ   or   2x = -arccos(1/3) + 2nπ]

(where n is any integer)

[2x = 2nπ   or   2x = π + 2nπ]

… … …   or   [2x = arccos(1/3) + 2nπ   or   2x = -arccos(1/3) + 2nπ]

[x = nπ   or   x = π/2 + nπ]

… … …   or   [x = 1/2 arccos(1/3) + nπ   or   x = -1/2 arccos(1/3) + nπ]

7 0
3 years ago
PLZZZZ HELP WITHT THISSSS
IRISSAK [1]

Answer:

lol idk my butthole stinke

Step-by-step explanation:

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