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3 years ago

12

. Mrs. Nunn pours 3 juice boxes into a bowl to make punch. Each juice box holds 236 milliliters. How much juice does Mrs. Goldst

ein pour into the bowl? *

1 answer:

Novay_Z [31]3 years ago

7 0

Answer:

708 milliliters

Step-by-step explanation:

There are 3 juice boxes and each contain 236 milliliters of juice. So 236 + 236 + 236 = 708

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On a final exam, each multiple-choice question is worth 4 points and each word problem is worth 8 points. Lorenzo needs at least

Alexeev081 [22]

The correct multiple choice questions (x) are 4 points each.
The correct word problems (y) are 8 points each.
Lorenzo needs AT LEAST 50 points.
Put all that information into an inequality and you get:
4x + 8y ≥ 50

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3 years ago

Read 2 more answers

According to the guideline from the Health Department, every over-weight child needs to take a fitness test. Every ten over-weig

nlexa [21]

Answer:

The expected number of children that can pass the fitness test in a test session is 7.5 and the standard deviation is 1.37.

Step-by-step explanation:

For each children, there are only two possible outcomes. Either they pass the health test, or they do not. Whether a child can pass the test is independent with the test result of other children. This means that we use the binomial probability distribution to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

The probability for each child to pass the fitness test is 0.75

This means that $p = 0.75$

10 independent children

This means that $n = 10$ Find the expectation and standard deviation of the number of children can pass the fitness test in a test session.

$E(X) = np = 10*0.75 = 7.5$

$\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{10*0.75*0.25} = 1.37$

The expected number of children that can pass the fitness test in a test session is 7.5 and the standard deviation is 1.37.

4 0

3 years ago

For each of the following functions, determine if they are injective. Also determine if theyare surjective. Also determine if th

timurjin [86]

Answer:

Check below

Step-by-step explanation:

1. Definition for intervals

$(a,b)=\left \{ x\in\Re : a$

2. Functions

1) $\Re \rightarrow \Re \\ f(x)=x$

Let's perform graph tests.

That's an one to one, injective function. Look how any horizontal line touches that only once. Also, It's a surjective and a bijective one.

2) $\Re\geq0\rightarrow\Re , f(x)=x+1\\$

Injective, surjective and bijective.

Injective: a horizontal line crosses the graph in one point.

3) $f:\Re\geq 0\rightarrow\Re, f(x) = cos(x)$

The cosine function is not injective, bijective nor surjective.

4) $f:\Re\rightarrow\Re \:f(x)=ex$

Since e, is euler number it's a constant. It's also injective, surjective and bijective.

5) Quite unclear format

$6) \:f:\Re\rightarrow(0,\infty), f(x) =ex$

Despite the Restriction for the CoDomain, the function remains injective, surjective and therefore bijective.

$7) f:\Re\geq 0 \rightarrow \Re\geq0, f(x) =x^{4}$

Not injective nor surjective therefore not bijective too.

$8).f:\{-1,2,-3\}}\rightarrow \{1,4,9\}, f(x) =x^{2}$

$f(-1)=1, f(2)=4, f(-3)=9$

Injective (one to one), Surjective, and Bijective.

$10) f:\Re\geq 0\rightarrow [-1,1], f(x)= cos(x)\\-1=cos(x) \therefore x=\pi,3\pi,5\pi,etc.$

Surjective.

$11.f:R\geq 0[-1,1], f(x) = 0\\$

Surjective

12.f: US Citizens→Z, f(x) = the SSN of x.

General function

13.f: US Zip Codes→US States, f(x) = The state that x belongs to.

Surjective

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3 years ago

The sum of a positive number and a negative number is positive when...

anyanavicka [17]

When the absolute value of the positive number is higher than the absolute value of the negative number.

4 0

3 years ago

If one card is drawn from an ordinary deck of cards what is the probability of getting a red card or a 10 or a queen?

Scilla [17]

Answer:

$\frac{17}{26}$

Step-by-step explanation:

In probability

"AND" means to multiply, and

"OR" means to add

Here, we want probability getting a red card OR a 10 OR a queen. So we find each individual probabilities and ADD.

In a standard deck, there is 52 cards.

<u>P(Red):</u>

half the cards are red and half are black, so there are 52/2 = 26 red cards

Hence

P(Red) = 26/52 = 1/2

<u>P(10):</u>

There are 4 suits with each one having 1 "10" card, so there are FOUR 10s in a deck. So,

P(10) = 4/52 = 1/13

<u>P(Queen):</u>

There are 4 suits with each one having 1 Queen. So in 4 suits, there are a total of 4 Queens. So,

P(Queen) = 4/52 = 1/13

P(Red, or, 10, or, Queen) = 1/2 + 1/13 + 1/13 = $\frac{17}{26}$

4 0

3 years ago