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Mamont248 [21]
3 years ago
6

find the absolute maximum and the absolute minimum of the given function on the given interval f(x)=xe^x/2 on [-3,1]

Mathematics
2 answers:
Liono4ka [1.6K]3 years ago
8 0

Answer:

View the graph for a visual

Step-by-step explanation:

damaskus [11]3 years ago
6 0

Answer:

Step-by-step explanation:

f(x)=xe^{\frac{x}{2} } \\f'(x)=x*\frac{1}{2} e^{\frac{x}{2} } +e^{\frac{x}{2} } =e^{\frac{x}{2} } (\frac{x}{2} +1)\\

f'(x)=0, gives x=-2

we find f(x) at x=-3,-2,1

f(-3)=-3e^(-3/2)≈-0.67

f(-2)=-2e^(-2/2)=-2e^{-1}=-2/e≈-0.74

f(1)=1 e^(1/2)=√e≈1.65

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algol [13]

The domain is the set of allowed x inputs, or x coordinates of a function. In this case, any point on the curve has an x coordinate that is 4 or smaller.

Therefore, the domain is the set of numbers x such that x \le 4

To write this in interval notation, we would write (-\infty, 4] This interval starts at negative infinity and stops at 4. We exclude infinity with the curved parenthesis and include 4 with the square bracket.

-----------------------------------------------------------------------

The range is the set of possible y outputs. Every point on this curve has a y coordinate that is either 0 or it is larger than 0.

The range is the set of y values such that y \ge 0

In interval notation, it would be written as [0, \infty) This time we start at 0 (including this endpoint) and "stop" at infinity

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If f(x) = 3x^2 + 1 and g(x) = 1 – x, what is the value of (f – g)(2)?
ziro4ka [17]
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Answer:

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Step-by-step explanation:

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