Find the geometric mean of 125 and 5

Please help me i beg of u due today my teacher be buggin

mart [117]

Answer:

1) 35+5w=110

2) the starting heart rate is 73 beats per minute

3)B

4) 6mins

Step-by-step explanation:

1) since she deposits 5 dollars each week we can multiply 5 and w to find out how much money hes depositing after all the weeks are done. We need to add that with 35 to get the TOTAL money in the bank account.

2) 73 is the y intercept. The y intercept is the number when "x" is 0. So when hes just starting out/not excersizing his heart beats 73 beats per min.

3) we know that 10% of her tips is given back to her hence x(number of tips) is multiplied by 0.1, and added to 50 to find the total amount of money she receives

4) 6 mins for 1 order

6 0

3 years ago

If you know this pls help ):

Aleksandr-060686 [28]

From the right hand side, we will need to find a way to rewriting 3x²y in terms of cube roots.
We know that 27 is 3³, so if we were to rewrite it in terms of cube roots, we will need to multiply everything by itself two more twice. (ie we can rewrite it as ∛(3x²y)³)

Hence, we can say that it's:
$\sqrt[3]{162x^{c}y^{5}} = \sqrt[3]{(3x^{2}y)^{3}} * \sqrt[3]{6y^{d}}$
$= \sqrt[3]{162x^{6}y^{3+d}}$

Hence, c = 6 and d = 2

4 0

3 years ago

Evaluate: -30 ÷ 2 a. 10 b. 15 c. -15 d. -10

faust18 [17]

C......................

7 0

2 years ago

Read 2 more answers

While conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modem

Kitty [74]

Answer:

We conclude that this is an unusually high number of faulty modems.

Step-by-step explanation:

We are given that while conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modems.

The probability of obtaining this many bad modems (or more), under the assumptions of typical manufacturing flaws would be 0.013.

Let p = population proportion.

So, Null Hypothesis, $H_0$ : p = 0.013 {means that this is an unusually 0.013 proportion of faulty modems}

Alternate Hypothesis, $H_A$ : p > 0.013 {means that this is an unusually high number of faulty modems}

The test statistics that would be used here One-sample z-test for proportions;

T.S. = $\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion faulty modems= $\frac{10}{367}$ = 0.027

n = sample of modems = 367

So, the test statistics = $\frac{0.027-0.013}{\sqrt{\frac{0.013(1-0.013)}{367} } }$

= 2.367

The value of z-test statistics is 2.367.

Since, we are not given with the level of significance so we assume it to be 5%. Now at 5% level of significance, the z table gives a critical value of 1.645 for the right-tailed test.

Since our test statistics is more than the critical value of z as 2.367 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that this is an unusually high number of faulty modems.

6 0

3 years ago

Find the coordinates of the vertices of the figure formed by each system of inequalities.

siniylev [52]

Answer:

D(1, –5), (7, 1), (–11, 7)

Step-by-step explanation:

The given inequalities are:

y + x ≥ –4

y ≥ x – 6

3y + x ≤ 10

We graph the inequalities as shown in the attachment.

The coordinates of the vertices of the figure formed by the given system of inequalities are:

(1, –5), (7, 1), (–11, 7)

The correct choice is D.

6 0

3 years ago