Question

How many grams of glycerine, C3H8O3, are needed to make 100. mL of 2.60 M solution?

Answer 1

Answer:

the mass of the glycerine needed in the given solution is  23.92 g

Explanation:

Given;

molarity of the solution (C₃H₈O₃), C = 2.60 M

Volume of the solution, V = 100 mL = 100 x 10⁻³ L = 0.1 M

The molarity of a solution is given as follows;

$Molarity = \frac{amount \ of \ solute \ (moles)}{volume \ of \ solution \ (L)} \\\\amount \ of \ solute \ (moles) = Molarity \ \times volume \ of \ solution \ (L)\\\\amount \ of \ solute \ (moles) = 2.6 \times 0.1 \\\\amount \ of \ solute \ (moles) = 0.26 \ mole$

The molecular mass of the given solution;

molecular mass = (12 x 3) + (8 x 1) + (16 x 3)

molecular mass = 92 g/mol

The mass of the glycerine needed in the given solution is calculated as follows;

reacting mass = amount of solute (moles)   x   molecular mass (g/mol)

reacting mass = 0.26 x 92

reacting mass = 23.92 g

Therefore, the mass of the glycerine needed in the given solution is  23.92 g