All categories

3 years ago

Pls help I’ll brainlest

Mathematics

1 answer:

musickatia [10]3 years ago

3 0

Answer:

1) 5 paychecks

2) $105

3) $410 leftover

Hope this helps!

Maybe brainliest?

You might be interested in

bogdanovich [222]

Answer:

12$ an hour

Step-by-step explanation:

60 minutes in an hour 15 times 4= 60 which is one hour, so 4 times 3 equals 12 which is the answer

4 0

2 years ago

Read 2 more answers

Factor each expression (9 & 10)

s344n2d4d5 [400]

9)
8x+4*6
8x+24

11)
3t+2c=6tc

7 0

3 years ago

:( help? please.. i need help

Oduvanchick [21]

The answer is 64 because they are alternate interior angles. Alternate interior angles are always congruent.

5 0

3 years ago

It is known that the straight line l is tangent to the circle x^2+y^2=4 at a point on the x-axis, and intersects with the straig

Talja [164]

Step-by-step explanation:

The general equation of a circle is

$(x \ - \ h)^2 \ + \ (y \ - \ k)^2 \ = \ r^{2}$ ,

where h and k forms the coordinates of the centre of the circle.

When the circle has a centre at the origin, the equation reduces into

. $x^2 \ + \ y^2 \ = r^2$ .

Now, we are interested in solving for the x-intercepts (the x-coordinates when the circle intersects the x-axis), of the circle

$x^2 \ + \ y^2 \ = \ 4$ .

Thus,

$x^2 \ + \ (0)^2 \ = \ 4 \\ \\ \\ \-\hspace{1.3cm} x^{2} \ = \ 4 \\ \\ \\ \-\hspace{1.4cm} x \ = \ \pm \ 2$ .

Geometrically speaking, the tangent to the circle at the point defined by one of the x-intercepts of the circle is actually a vertical line, more specifically the lines $x \ = \ \pm \ 2$ .

First and foremost, for the vertical line $x \ = \ 2$ , it intersects the straight line $y \ = \ \displaystyle\frac{1}{2}x$ , giving the y-coordinate for point P,

$y \ = \ \displaystyle\frac{1}{2}(2) \\ \\ \\ y \ = \ 1$ .

Hence, the coordinates of point P are $(1, \ 1)$ .

However, since there are no boundaries given in the question and a circle is symmetrical about its centre, thus, point P also exists when the vertical line $x \ = \ -2$ and interdects the straight line $y \ = \ \displaystyle\frac{1}{2}x$ .

$y \ = \ \displaystyle\frac{1}{2}(-2) \\ \\ \\ y \ = \ -1$ .

Therefore, the coordinates of point P are also $(1, \ -1)$ .

8 0

2 years ago

What is 700070.07 is standard form??

mojhsa [17]

The standard form is

8 0

3 years ago

Read 2 more answers