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3 years ago

Omggggggggg please please help meeeeeeeeee

Mathematics

2 answers:

Lera25 [3.4K]3 years ago

8 0

Answer:

Step-by-step explanation:

9-7= 2

2<3

Wittaler [7]3 years ago

8 0

Answer: B

x < 10

Step-by-step explanation:

X - 7 < 3

X < 3 + 7

X < 10

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Carlo recycles 8 glass bottles every week. Which expression shows the total number of glass bottles he recycles in w weeks?

Lena [83]

8w

he recycles 8 per week which means if you wanted to know how many he had recycled after 10 weeks you would multiply 8 by 10 to find out. so its 8w

6 0

3 years ago

Read 2 more answers

Can someone answer this please and thank you

musickatia [10]

Answer:

See below.

Step-by-step explanation:

x+3/9=5/9

-3/9 -3/9

x=2/9

--------------

11+x=50

-11 -11

x=39

-------------

2/9+x=8/9

-2/9 -2/9

x=6/9 or 2/3

-hope it helps

7 0

3 years ago

A collection of 30 gems, all of which are identical in appearance, are supposedto be genuine diamonds, but actually contain 8 wo

levacccp [35]

Answer:

Step-by-step explanation:

From the given information:

There are 30 collections of gems, of which 8 are worthless;

Thus, the number of the genuine diamonds = 30 - 8 = 22.

Let X = random variable;

X consider the value as 0 (for 2 worthless stone selection),

X = 1200(1 worthless stone & 1 genuine stone)

X = 2400 (2 genuine stones selected)

However, the numbers of ways of selecting and chosen Gems can be estimated as:

$(^n_r) = (^{30}_2) \\ \\ \implies \dfrac{30!}{2!(30-2)!} \\ \\ \implies \dfrac{30!}{2!(28)!} \\ \\ \implies \dfrac{30*29*28!}{2!(28)!} \\ \\ \implies \dfrac{30*29}{2*1} \\ \\ \implies 435$

Thus;

$Pr (X = 0) = \dfrac{(^8_2)}{435}$

$Pr (X = 0) = \dfrac{\dfrac{8!}{2!(8-2)!}}{435} \\ \\ Pr (X = 0) = \dfrac{\dfrac{8!}{2!(6)!}}{435} \\ \\ Pr (X = 0) = \dfrac{\dfrac{8*7*6!}{2!(6)!}}{435} \\ \\ Pr (X = 0) = \dfrac{\dfrac{8*7}{2*1}}{435} \\ \\ Pr (X = 0) = 0.0644$

$P(X =1200) = \dfrac{(^{8}_{1})(^{22}_{1})}{435}$

$P(X =1200) = \dfrac{ \dfrac{8!}{1!(8-1)!}) ( \dfrac{22!}{1!(22-1)!}) }{435}$

$P(X =1200) = \dfrac{ (8) ( 22) }{435}$

$P(X =1200) =0.4046$

$Pr (X = 2400) = \dfrac{(^{22}_2)}{435}$

$Pr (X = 2400) = \dfrac{\dfrac{22!}{2!(22-2)!}}{435} \\ \\ Pr (X = 2400) = \dfrac{\dfrac{22!}{2!(20)!}}{435} \\ \\ Pr (X = 2400) = \dfrac{\dfrac{22*21*20!}{2!(20)!}}{435} \\ \\ Pr (X =2400) = \dfrac{\dfrac{22*21}{2*1}}{435} \\ \\ Pr (X = 2400) = 0.5310$