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Mice21 [21]
3 years ago
15

Please help tyyyyyyyyy!

Mathematics
1 answer:
VladimirAG [237]3 years ago
6 0
The answer is a 3% jewnsnsnddksk
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Find the volume of the cylinder height 10 in base radius 3 in
tino4ka555 [31]

Answer: 282.60in³

Step-by-step explanation:

When calculating the volume of a cylinder, the formula to use is:

= πr²h

where,

π = 3.14

r = radius = 3 in

h = height = 10 in

Volume = πr²h

= 3.14 × 3² × 10

= 282.60

Therefore, the volume of the cylinder is 282.60in³

3 0
3 years ago
NEED HELP LOTS OF POINTS!!! Diego had $21.32 and gave $9.50 to Elena. How much did he have left?
erastovalidia [21]

Answer:

11.18

Step by Step Explanation:

Subtract 9.5 from 21.23

8 0
3 years ago
If SR is 4.5cm and TR is 3cm, what is the measure in degrees of angle S?
kow [346]

Answer: The measure in degrees of angle S is 33.7°

Step-by-step explanation: Please see the attachments below for the complete question as well as the Step-by-step explanation

5 0
3 years ago
How to find a slope
exis [7]

Answer:

Step-by-step explanation:

y₂₋y₁ / x₂-x₁   if you have two points you can plug them in and find the slope using this.

If it is on a graph you can look at two points and count the rise over run, for example if one point is (0, 0) and another is (2, 3) then from the first point it goes up 2 and over 3, so the slope would be 2/3

5 0
3 years ago
Find f. f ″(x) = x^−2, x > 0, f(1) = 0, f(6) = 0
marin [14]

If you do in fact mean f(1)=f(6)=0 (as opposed to one of these being the derivative of f at some point), then integrating twice gives

f''(x) = -\dfrac1{x^2}

f'(x) = \displaystyle -\int \frac{dx}{x^2} = \frac1x + C_1

f(x) = \displaystyle \int \left(\frac1x + C_1\right) \, dx = \ln|x| + C_1x + C_2

From the initial conditions, we find

f(1) = \ln|1| + C_1 + C_2 = 0 \implies C_1 + C_2 = 0

f(6) = \ln|6| + 6C_1 + C_2 = 0 \implies 6C_1 + C_2 = -\ln(6)

Eliminating C_2, we get

(C_1 + C_2) - (6C_1 + C_2) = 0 - (-\ln(6))

-5C_1 = \ln(6)

C_1 = -\dfrac{\ln(6)}5 = -\ln\left(\sqrt[5]{6}\right) \implies C_2 = \ln\left(\sqrt[5]{6}\right)

Then

\boxed{f(x) = \ln|x| - \ln\left(\sqrt[5]{6}\right)\,x + \ln\left(\sqrt[5]{6}\right)}

3 0
2 years ago
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