The length of the midsegment of an isosceles trapezoid is the sum of the two bases, divided by 2. So this means -

(base 1+base2) / 2

(12+20) / 2

32/2

Length of midsegment = 16

6 0

3 years ago

How many blocks with dimensions of One-third times 1 times 1 can fit in a unit cube?

gtnhenbr [62]

Answer: 3

Step-by-step explanation:

Given

The dimension of the small block is

$\dfrac{1}{3}\times 1\times 1$

The Volume of the cube having unit length is

$V=1\times 1\times 1\\V=1\ unit^3$

The number of blocks that can be in the unit cube is the division of the volume of the unit cube and block.

$\Rightarrow \dfrac{1\times 1\times 1}{\dfrac{1}{3}\times 1\times 1}\\\\\Rightarrow \dfrac{3}{1}=3$

7 0

3 years ago

Read 2 more answers

Help please.

Murljashka [212]

Add up them up
Ab+BC
18.3+11.2
=29.5

5 0

2 years ago

What is the value of (−23) –[(−25) – {(−17) –(−19)}

o-na [289]

The answer is four.

5 0

3 years ago